Convert 112km/h to ms^2: Step-by-Step Guide

  • Thread starter Thread starter nads_82
  • Start date Start date
  • Tags Tags
    Units
AI Thread Summary
To convert 112 km/h to m/s², first convert km/h to m/s by multiplying by 1000 and dividing by 3600, resulting in approximately 31.11 m/s. Then, to find acceleration in m/s², divide by the time in seconds, which is 60 seconds for a minute. The calculated acceleration is approximately 0.5185 m/s². The initial calculation of 0.5183 m/s² was close but slightly off. The conversion method used was correct, confirming the approach to the problem.
nads_82
Messages
2
Reaction score
0
How do I convert 112km/h/min to ms^2?
 
Physics news on Phys.org
You have 3600 \frac s {hr} [/tex] and 60 \frac s {min}<br /> <br /> Do the algebra.
 
I have had a go at trying to work this out but not sure if my answer is correct. I got a result of 0.5183ms-2. Is this right?
 
From km/h to m/s you multiply by 1000 and divide by 3600, from m/s to km/h you multiply by 3.6 (3600/1000).
 
nads_82 said:
I have had a go at trying to work this out but not sure if my answer is correct. I got a result of 0.5183ms-2. Is this right?

It looks more to me like 0.5185m/s^2, but yes, you have the right idea.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Displacement of 1971 Dodge Challenger: 113m?
Replies
3
Views
1K
Conversion factor when converting from SI to natural units
Replies
1
Views
802
Kinematics Question with weird units
Replies
5
Views
1K
I Unit Conversions of Force: How to Convert Between Different Units of Force?
Replies
4
Views
1K
Measurements Calculation Problem
Replies
3
Views
856
Golf club 🏌️and ball ⛳ impulse problem
Replies
19
Views
2K
Different sunset times due to elevation ##h## at a point on the Earth
Replies
13
Views
1K
Find the electric field between 2 finite discs
Replies
16
Views
1K
Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
Replies
44
Views
6K
How much of the wooden timber was submerged in water?
Replies
2
Views
1K

Hot Threads

Recent Insights

Back
Top