Convert 2000 Ft Lbs Torque to Pounds - Electric Brake

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SUMMARY

The discussion centers on converting 2000 ft lbs of torque into linear weight using a 100-foot lever (boom). The calculation reveals that the force at the end of the boom is 20 lbs when using the formula 2000 ft lbs divided by the lever length of 100 feet. The diameter of the electric brake, which is 15 inches, is only relevant for torque computation and does not affect the linear weight calculation. Understanding the relationship between torque, lever length, and force is crucial for accurate conversions.

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leverage
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Does anyone know how to convert 2000 ft lbs of torque into linear weight? I have an electric brake capable of holding 2000 lbs of torque. But i don't know how to convert to actual pounds that can hold. It also involves a 100 foot lever( boom). What would the force in pounds be? the brake itself is about 15 inches in diameter.
 
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It depends on how far from the fulcrum the weight is attached. The closer to the fulcrum, the higher the force you can achieve with the same torque.
“Give me a lever long enough and a fulcrum on which to place it, and I shall move the world.” Archimedes
 
leverage said:
Does anyone know how to convert 2000 ft lbs of torque into linear weight? [...] It also involves a 100 foot lever( boom).
If I understand you correctly that you need to know how much weight can be supported at the end of a 100 foot boom by 2000 ft lbs, it's 2000 ft lbs / 100ft = 20 lb. If it's some other distance from the pivot, substituted that into the same formula.

Diameter of the brake itself is only relevant in computing the torque. Once you know the torque, it doesn't make a difference.
 

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