Converting Cartesian to Polar Coordinates: Explained with Example

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SUMMARY

The discussion focuses on converting Cartesian coordinates (-3, 4) into polar coordinates, resulting in (5, π - arctan(4/3)). The calculation of r as 5 is confirmed using the formula r = sqrt(x² + y²). The angle θ is derived from the arctangent function, adjusted by π to account for the location of the point in the second quadrant. The necessity of this adjustment is clarified by the properties of the arctan function, which only provides values in the first and fourth quadrants.

PREREQUISITES
  • Understanding of Cartesian and polar coordinate systems
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with the arctangent function and its range
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the properties of the arctangent function and its range
  • Learn about the conversion formulas between Cartesian and polar coordinates
  • Explore the unit circle and its relation to trigonometric functions
  • Practice converting various Cartesian coordinates to polar coordinates
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in mastering coordinate transformations in geometry.

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Homework Statement


Find polar coordinates.


Homework Equations


Cartesian: (-3,4)


The Attempt at a Solution


r = sqrt(9+16) = 5
sinθ = 4/5
cosθ = -3/5

θ = ∏ - arctan(4/3)

Answer: (5, ∏ - arctan(4/3))


I do not understand why we have subtracted the value arctan(4/3) from pi?
 
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What is the range of arctan? And where is the point really located?
 
Because the Cartesian coordinates (-3,4) are in 2th Quadrant
 

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