Converting Kcal/day to umol/g/h

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Homework Help Overview

The discussion revolves around converting kilocalories per day to millimoles per gram per hour, specifically in the context of Basal Metabolism Rates (BMR) in physiology. The original poster seeks clarity on the conversion process without a specific chemical reaction involved.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the conversion of energy units and question the relevance of metabolic reactions. Some inquire about the specifics of the metabolism process and the necessary parameters for conversion.

Discussion Status

The conversation is ongoing, with participants providing insights into the nature of the metabolism being discussed. There is a focus on understanding the underlying assumptions and parameters needed for the conversion, though no consensus has been reached.

Contextual Notes

The original poster clarifies that the conversion is not related to a chemical reaction but rather to physiological measurements, indicating a potential gap in the information required for the conversion.

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Homework Statement


*Sorry, I got the prefix in the subject wrong... it's supposed to be KCal/day to mmol/g/h, not micromoles
How do I convert kilocalories/day to millimoles/g/h?

Homework Equations


Obviously there are 24 hours in a day, but I don't know how to go from KCal to millimol/g
 
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Presumably you have some reaction(s) to which you want to apply this to? Do you have any enthalpy or free energy changes available?
 


No, it's not a chemical reaction. We're working with Basal Metabolism Rates (BMR) in physiology right now, where BMR is measured in kilocalories/day. I need to convert it to millimoles/g/h to apply it to the weight of a mouse.
So I just need to know how to convert the units.
 
Well, do you know what it is you're metabolising?

If you have a reaction that gives off e.g. 100 kcal / mol, and that the molecular weight of your substrate is e.g 500 g / mol, you can say that the reaction gives off 0.2 kcal / g. Not sure if that helps?
 

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