Converting Kcal/day to umol/g/h

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To convert kilocalories per day to millimoles per gram per hour, one must consider the specific metabolic reaction involved, as the conversion depends on the energy yield of the substrate being metabolized. The discussion highlights the importance of knowing the enthalpy or free energy changes associated with the metabolism of the substance in question. It is noted that for Basal Metabolism Rates (BMR), which are measured in kilocalories per day, the conversion requires understanding the molecular weight of the substrate. A suggested approach involves calculating the energy yield per gram based on the reaction's energy output and the molecular weight of the metabolized compound. Ultimately, the conversion is contingent on the specific metabolic context and the properties of the substrate.
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Homework Statement


*Sorry, I got the prefix in the subject wrong... it's supposed to be KCal/day to mmol/g/h, not micromoles
How do I convert kilocalories/day to millimoles/g/h?

Homework Equations


Obviously there are 24 hours in a day, but I don't know how to go from KCal to millimol/g
 
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Presumably you have some reaction(s) to which you want to apply this to? Do you have any enthalpy or free energy changes available?
 


No, it's not a chemical reaction. We're working with Basal Metabolism Rates (BMR) in physiology right now, where BMR is measured in kilocalories/day. I need to convert it to millimoles/g/h to apply it to the weight of a mouse.
So I just need to know how to convert the units.
 
Well, do you know what it is you're metabolising?

If you have a reaction that gives off e.g. 100 kcal / mol, and that the molecular weight of your substrate is e.g 500 g / mol, you can say that the reaction gives off 0.2 kcal / g. Not sure if that helps?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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