When a liquid is cooled, the difference between the tempurature of the liquid and the surrondings is measured. The results are:(adsbygoogle = window.adsbygoogle || []).push({});

t(min) 10 20 30 40

T(°C) 60.7 36.8 22.3 13.5

Where t= time from the start of the cooling

T= tempurature difference

Q(i) Process the above data and show that the cooling curve has the form:

T=Ae^(-kt)

I'm not sure how to do this. I have gone through the text book and there are no similar questions to this. The only one close has a different form.

I tried getting a value for A using a computer programme, but it said that there is no algebraic solution. I also tried getting a value for -k that worked but i'm not sure how to transform this data to show a cooling curve.

b) Find the values of A and k.

Thanks for any help.

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# Homework Help: Cooling Curve

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