When a liquid is cooled, the difference between the tempurature of the liquid and the surrondings is measured. The results are: t(min) 10 20 30 40 T(°C) 60.7 36.8 22.3 13.5 Where t= time from the start of the cooling T= tempurature difference Q(i) Process the above data and show that the cooling curve has the form: T=Ae^(-kt) I'm not sure how to do this. I have gone through the text book and there are no similar questions to this. The only one close has a different form. I tried getting a value for A using a computer programme, but it said that there is no algebraic solution. I also tried getting a value for -k that worked but i'm not sure how to transform this data to show a cooling curve. b) Find the values of A and k. Thanks for any help.