Coordinate charts to cover a circle?

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SUMMARY

The discussion centers on the minimal number of charts required to cover a circle and a sphere. It is established that two charts are sufficient to cover a circle, specifically defined as (-α < θ < π + α) and (π - α < θ < 2π + α), where α is a small number. The conversation also mentions that while four charts can be derived using a specific method involving upper and lower halves of the circle, two remain the minimal requirement. For a sphere, six charts can be generated, but again, only two are necessary, typically found through stereographic projection.

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pivoxa15
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4 charts seem to cover it. BUt only 2 will do for a minimal number?

Just like 2 charts will do to cover a sphere? Even though there are 6 all together.
 
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I'm not sure why you add that "6 altogether". What 6 charts are you talking about? Yes, of course, two charts will cover a circle. Choose one as [itex](-\alpha < \theta < \pi+ \alpha)[/itex] and the other [itex](\pi-\alpha < \theta < 2\p+ \alpha )[/itex] where [itex]\alpha[/itex] is some small number.
 
i think we are agreed that you can cover a circle with different number of charts but 2 is the minimal number
what you ask is possibly a special way of finding charts.
I guess the method you use is for circle first taking upper half of circle(of course as an open set the end points are not included) than letting any point (x,y) on circle to go (x,0) for example.this gives first chart ,doing same for the lower half gives second one .and for each remaining two points (end points of the half circle) we take a open nhd and suitable hom. So you obtain 4 charts
same method gives for sphere 6 charts but 2 is enough (which is found by different methods.the latter is found by stereographic projection usually)
 

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