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How fast do these imaginary signals travel? What are the rules?cianfa72 said:o be as clear as much as possible, suppose it was possible to exchange sound signals in vacuum
In the absence of rules, no prediction can be made.
How fast do these imaginary signals travel? What are the rules?cianfa72 said:o be as clear as much as possible, suppose it was possible to exchange sound signals in vacuum
Dale said:It is the same with proper time. Why are you willing to accept that something as physical as the odometer reading can be changed without some mechanism that we can point to that is changing it, but not proper time? They are equivalent. The difference in both cases is the path, not a change to the measuring device.
I don't understand this statement. Are you saying that paths are unphysical so you don't accept the fact that two cars traveled on different paths as the physical reason that their odometers read differently? If so, then what is the physical reason for the different odometer readings? If you can answer that question then there should be an analogous answer for the proper time question. Personally, the fact that the paths are different lengths seems like a sufficient answer to me.Jimster41 said:I’m not “willing to accept” that there are unphysical things such “paths” vs odometers that are physical.
The second, symbol s, is the SI unit of time. It is defined by taking the fixed numerical value of the caesium frequency ##\Delta\nu_{Cs}##, the unperturbed ground-state hyperfine transition frequency of the caesium-133 atom, to be 9 192 631 770 when expressed in the unit Hz, which is equal to s^–1.Jimster41 said:Question for you: what’s a second?
In the case of an odometer and a path in three dimensions, experiment shows that acceleration has no effect.Jimster41 said:I am saying the path and it’s effect on my the odometer including the effect of acceleration on that effect
If you are willing to accept the path as being the physical cause of the effect for the odometer then it should be no problem to accept the path as being the physical cause for the effect for a clock too.Jimster41 said:I am saying the path and it’s effect on my the odometer including the effect of acceleration on that effect must be physical.
Actually, it is the BIPM, not NIST.Jimster41 said:And yes I was hoping we’d agree that a human outfit called NIST had come up with a scheme to calibrate all our aging to one thing... a quantum mechanical thing.
What causes two paths in spacetime be of different length?jbriggs444 said:In the case of an odometer and a path in three dimensions, experiment shows that acceleration has no effect.
Noted. My mistake.Dale said:Actually, it is the BIPM, not NIST.
I accept that what you are calling "path" is the physical cause. I am asking what the "path" is physically and how the odometer knows how much of it is being covered? And if two spacetimes paths can be of different length because a) there was some acceleration that caused them to have different inertial frames or b) they are like, what, separated on a curved spacetime manifold? My question is how does the odometer account for and "know about" that?Dale said:If you are willing to accept the path as being the physical cause of the effect for the odometer then it should be no problem to accept the path as being the physical cause for the effect for a clock too.
The path is physically the set of all events at which the odometer/clock was located.Jimster41 said:I am asking what the "path" is physically and how the odometer knows how much of it is being covered?
Neither a nor b is correct in my opinion. They are different simply because they cover a different set of events. The acceleration or curvature certainly may be present and may even be necessary in certain circumstances, but it is incidental. The paths are different because they are different sets of events.Jimster41 said:And if two spacetimes paths can be of different length because a) there was some acceleration that caused them to have different inertial frames or b) they are on like, what, separated on a curved spacetime manifold.
The odometer/clock does not need to "know about" any difference between its path and any other path. All it does is measure the length of the path that it covers. The length of other paths that it does not cover is not relevant to its functioning.Jimster41 said:Then my question is how does the odometer account for and "know about" that?
Yes, certainly. Although what we are talking about here applies to both GR and QFT individually.Jimster41 said:You do agree there is currently no quantum mechanical theory of general relativity right?
Assume those imaginary signals travel at constant speed ##s## other than the speed of light.jbriggs444 said:How fast do these imaginary signals travel? What are the rules?
In the absence of rules, no prediction can be made.
As measured in what frame?cianfa72 said:Assume those imaginary signals travel at constant speed ##s## other than the speed of light.
Right question...I believe the same topic applies for the light beams. How can we "manage" it in that case ?jbriggs444 said:As measured in what frame?
It turns out that all inertial frames will measure the same speed for anything moving at c. But in the case at hand, s is not equal to c. So frame choice matters.cianfa72 said:Right question...I believe the same topic applies for the light beams. How can we "manage" it in that case ?
Dale said:Neither a nor b is correct in my opinion. They are different simply because they cover a different set of events. The acceleration or curvature certainly may be present and may even be necessary in certain circumstances, but it is incidental. The paths are different because they are different sets of events.
Dale said:The odometer/clock does not need to "know about" any difference between its path and any other path. All it does is measure the length of the path that it covers. The length of other paths that it does not cover is not relevant to its functioning.
ok sure you're right. Thus if just light has the same speed ##c## in any and all inertial frame, are we still able to exploit those imaginary signals to define the synchronization among coordinate clocks spatially separated ?jbriggs444 said:It turns out that all inertial frames will measure the same speed for anything moving at c. But in the case at hand, s is not equal to c. So frame choice matters.
Wait a bit. You've used a coordinate system to define a process and then used the process to define a coordinate system? Is that not a bit circular?cianfa72 said:ok sure you're right. Thus if just light has the same speed ##c## in any and all inertial frame, are we still able to exploit those imaginary signals to define the synchronization among coordinate clocks spatially separated ?
The same thing that causes two paths in space to have different length. If I drive from Miami to Denver and then to Boston while you drive from Miami to Washington DC and then on to Boston we will find that your odometer has counted fewer miles than mine. We have no problem saying that the odometer readings are different because we took different paths between Miami and Boston. If asked what caused the path through Denver to be longer, there may be no better answer than that different paths have different lengths. There's nothing different about the miles on the Miami-Denver-Boston path, there are just more of them than on the Miami-Washington-Boston path.Jimster41 said:What causes two paths in spacetime be of different length?
The odometer doesn't "know" anything. It just counts the miles/seconds as they pass by, and there are more of them to count along one path than along the other.And if two spacetimes paths can be of different length because a) there was some acceleration that caused them to have different inertial frames or b) they are like, what, separated on a curved spacetime manifold? Then my question is how does the odometer account for and "know about" that?
These events are just statements of the form "the twin was at this point in spacetime", just as the paths of the two cars are defined by statements of the form "the car passed by this point". The events themselves don't provide any information about path length; the path has a length whether a car drives along or not. We can assign meaning to the statement "the Miami-Denver-Boston path is longer than the "Miami-Washington-Boston path" without involving any evnts at all.I am asking what is different about the events of the accelerating twin? How do those events manifest to the odometer the length of the path... How do they provide information that will later be observed as evidence of difference in path length?
No, that was not my point.jbriggs444 said:Wait a bit. You've used a coordinate system to define a process and then used the process to define a coordinate system? Is that not a bit circular?
Edit: To be clear, you are talking about doing clock synchronization using imaginary signals that are defined to move at speed s relative to a particular coordinate system. Then you are talking about using this synchronization mechanism to define the time coordinate of the clocks making up your coordinate system, right?
You don’t need anything physical, including a road, in order to define the length of a curve in space—just the space itself and a metric. So it is with paths through spacetime.Jimster41 said:That is because there is literally more of a thing, road.
In GR, the math that describes the physical reality is geometry.it feels like you are invoking the idea that there is this abstract thing called "geometry" that underpins physical reality
That is fine, but it has nothing to do with the topic at hand.Jimster41 said:I'm admiring the mountain of Yang-Mills looking up at it.
The odometer is attached to a tire whose circumference is known to within experimental precision. The odometer counts the number of times that the tire rotates and multiplies by the circumference of the tire to obtain the length of the path.Jimster41 said:How do those events manifest to the odometer the length of the path... How do they provide information that will later be observed as evidence of difference in path length?
There is more distance. The road is just there to help the odometer measure the distance. In the absence of a road we would measure the distance another way, but the geometry remains.Jimster41 said:That is because there is literally more of a thing, road... what is the road in the case of the traveling twin?
Sorry about that. I did not mean to be insulting, but just wanted to make you aware that the direction that this conversation is heading makes me uncomfortable. This topic is simpler than you are making it out to be and you seem highly resistant to reasonable efforts to simplify and clarify.Jimster41 said:You can insult me. It’s true.
Sure, but you don't need Yang-Mills for describing the hyperfine transition, QED will suffice. You also do not need a quantum gravity theory, the geometric aspects here are already built into QED.Jimster41 said:But I thought we had established that the gold standard of “clock” is an observatory watching quantum mechanical events. I guess you have a better clock?
When you accelerate then your worldline is not straight. The odometer simply measures the distance on that non-straight worldline the same way that it measured distance on a straight worldline: it counts the number of revolutions of the wheel on the non-straight path and multiplies by the circumference.Jimster41 said:So how does that odometer work when you accelerate it. Why/how does the “geometry” change.
Why wouldn’t geometry be physical? I have a table here, it is about as physical a thing as there is. The top is flat and rectangular, the legs are equal lengths, all perpendicular to the top, and all parallel to each other. The geometry is an inherent part of what makes my physical table a table. How can you say its geometry isn’t physical?Jimster41 said:it feels like you are invoking the idea that there is this abstract thing called "geometry" that underpins physical reality but which itself is not physical
Jimster41 said:am asking what is different about the events of the accelerating twin?
Jimster41 said:So how does that odometer work when you accelerate it. Why/how does the “geometry” change.
Any comments about this point ? Thankscianfa72 said:No, that was not my point.
Starting from the beginning...the idea is to exploit the physical process propagation of an imaginary signal to assign coordinate time to coordinate clocks sitting on rockets hovering at radial coordinate ##r## and at rest each other. Starting from a far away standard clock (here coordinate time is one-to-one with proper time) we send such signals towards remote clocks assigning half the value of the two-way trip upon such signals reaching them. This way we defined a synchronization procedure to adjust the "zero" of each coordinate clocks.
Then we assume, as you highlighted in post #7, that the rate of each coordinate clock at ##r## is adjusted to tick at ##(1-R_s/r)^{-1/2}## of the local proper time (as insted measured locally by a standard clock).
This way we define a procedure to assign globally the coordinate time to each event (or in other words a global coordinate chart when including also the ##r, \theta, \phi## coordinates).
Now the point is: has the metric in this coordinate chart the same expression as in the well known Schwarzschild form ?
cianfa72 said:has the metric in this coordinate chart the same expression as in the well known Schwarzschild form ?
Thus even using different signals other than light beams to synchronize spatially separated coordinate clocks (or even other procedures), provided that coordinate clocks rates are "adjusted" properly (see post #7 about it), does it result in a standard Schwarzschild coordinate chart (obviously including the spatial coordinates) ?PeterDonis said:This coordinate chart is standard Schwarzschild coordinates, so yes.
cianfa72 said:even using different signals other than light beams to synchronize spatially separated coordinate clocks (or even other procedures), provided that coordinate clocks rates are "adjusted" properly (see post #7 about it), does it result in a standard Schwarzschild coordinate chart (obviously including the spatial coordinates) ?
Actually that was my point around all my posts: to define a coordinate chart for spacetime we need a procedure (possibly thought). Here for instance the nature of the signals involved and the clock synchronization procedure has to be specified in order to define the coordinate time. Then in that just defined coordinate chart the spacetime metric will be described accordinglyPeterDonis said:Unless you tell me specifically what other signals you are going to use, and what other clock synchronization procedure you are going to use, I have no idea.