Correct Calculation of Vertical Stress in Soil

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SUMMARY

The discussion centers on the calculation of vertical stress in soil, specifically addressing the assumptions regarding the saturation of sand above the groundwater table. Participants agree that the total vertical stress at the center of the clay may be incorrectly calculated if the 2m thick sand is assumed to be saturated. The correct approach involves calculating vertical stress by considering both dry and saturated unit weights of soil, as well as the saturated unit weight of clay. The introduction of a 30% sand porosity is suggested to quantify the error in vertical and effective stress calculations.

PREREQUISITES
  • Understanding of soil mechanics principles
  • Familiarity with vertical stress calculations in geotechnical engineering
  • Knowledge of unit weight concepts for dry and saturated soils
  • Basic grasp of porosity and its impact on soil behavior
NEXT STEPS
  • Learn about effective stress principles in soil mechanics
  • Study the impact of soil saturation on vertical stress calculations
  • Investigate methods for calculating soil porosity and its implications
  • Explore numerical methods for quantifying errors in geotechnical calculations
USEFUL FOR

Geotechnical engineers, civil engineering students, and professionals involved in soil stress analysis and foundation design will benefit from this discussion.

tzx9633

Homework Statement


In this question , i suspect the total vertical stress at the center of the clay is incorrect .

Homework Equations

The Attempt at a Solution


In the figure , we can see that the water table is art 2m below the sand . So , the 2m sand thick should be dry , am i right ? Only the 1m thick sand is moist / saturated with water .

so , when we are calculating the vertical stress , we have to divide the soil into 2 parts , which are (dry unit weight of soil x 2m ) + ( saturated unit weight of soil x 1m) + ( saturated unit weight of clay x 2m)
 

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tzx9633 said:

Homework Statement


In this question , i suspect the total vertical stress at the center of the clay is incorrect .

Homework Equations

The Attempt at a Solution


In the figure , we can see that the water table is art 2m below the sand . So , the 2m sand thick should be dry , am i right ? Only the 1m thick sand is moist / saturated with water .

so , when we are calculating the vertical stress , we have to divide the soil into 2 parts , which are (dry unit weight of soil x 2m ) + ( saturated unit weight of soil x 1m) + ( saturated unit weight of clay x 2m)
Well, the problem statement says that, in determining the vertical stress, "the sand above ground level may be assumed to be saturated." So, you are correct in your objection. But the question is, how much of an error does this approximation introduce? Why don't you assume a sand porosity of 30% and quantify the magnitude of the error introduced by this approximation in the vertical stress and in the effective stress at the center of the clay layer?
 
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Chestermiller said:
Well, the problem statement says that, in determining the vertical stress, "the sand above ground level may be assumed to be saturated." So, you are correct in your objection. But the question is, how much of an error does this approximation introduce? Why don't you assume a sand porosity of 30% and quantify the magnitude of the error introduced by this approximation in the vertical stress and in the effective stress at the center of the clay layer?
Do you mean this is a special case where the soil is assumed to be saturated above the groundwater table ??
 
tzx9633 said:
Do you mean this is a special case where the soil is assumed to be saturated above the groundwater table ??
Did I say that? No I didn't.
 
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Chestermiller said:
Did I say that? No I didn't.
then , why the soil is assumed to be saturated ?
 
tzx9633 said:
then , why the soil is assumed to be saturated ?
As you already pointed out, this is only an approximation. I would like for you to solve it with and without the approximation so you can compare the results. Do you think you can do that?
 
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