- #1
JustinLiang
- 81
- 0
I know that the following two graphs are the same:
x(t)=0.15cos(10.21t+pi)
x(t)=-0.15cos(10.21t)
But when I try to solve for t given x=0.94 for the first function, when I plug it into my calculator I get -0.22s and the second function I get 0.22s. For the question I am doing I have to use the first function to get 0.22s, does anyone know how?
x(t)=0.15cos(10.21t+pi)
x(t)=-0.15cos(10.21t)
But when I try to solve for t given x=0.94 for the first function, when I plug it into my calculator I get -0.22s and the second function I get 0.22s. For the question I am doing I have to use the first function to get 0.22s, does anyone know how?