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## Homework Statement

Hello! I've run into a problem at work and need a quick solution! Basically I need to work out the cut size of a curved bar. I have the chord length (650mm) and the radius' (1335mm) Obviously i need to calculate the inner most angle, then multiply my diameter by pi, divide by 360 then multiply by my new found angle to find arc length

## Homework Equations

Cosine rule A=b[itex]^{2}[/itex]+c[itex]^{2}[/itex]-a[itex]^{2}[/itex][itex]/[/itex]2bc

C=∏d

## The Attempt at a Solution

obviously c and b are both equal at 1335mm. so the triangle becomes isosceles

Arc length = ∏x2670/360 x (1335[itex]^{2}[/itex]+1335[itex]^{2}[/itex]- 650[itex]^{2}[/itex]/2x1335x1335)[itex]^{cos-1}[/itex]

this equation leaves us at 28.17°

then (2670x∏/360)x28.17=656mm

Only 6mm gain on the arc? is this normal? please help!

many thanks, connor.