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Cot[Arctan(y)] = tan[Arccot(y)] = 1/y

  1. Dec 22, 2009 #1

    can someone prove this please?

    cot[Arctan(y)] = tan[Arccot(y)] = 1/y
  2. jcsd
  3. Dec 22, 2009 #2
    cot(u) = 1/tan(u)

    cot(arctan(y)) = 1/tan(arctan(y))


    The other one's the same, with tan(u) = 1/cot(u) as the relationship.
  4. Dec 22, 2009 #3
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