WernerQH said:
With propagators reaching backwards in time, Bell nonlocality poses no problem for QFT either. And I see the measurement problem as a non-problem.
The measurement problem has a pragmatic answer, but it doesn't (yet, as far as I know) have a mathematically consistent answer that doesn't go beyond accepted quantum mechanics.
Suppose you have an electron that has a spin state ##\alpha |U\rangle + \beta |D\rangle## where ##|\alpha|^2 + |\beta|^2 = 1## and ##|U\rangle## and ##|D\rangle## are eigenstates of the z-component of spin with spin +1/2 and -1/2, respectively. Does this mean that the electron has a probability of ##|\alpha||^2## of being spin-up in the z-direction, and a probability of ##|\beta|^2## of being spin-down?
I think most people would say "no". Until it's measured, the particle doesn't have a spin in the z-direction. It's not that we just don't know what its spin is. As a matter of fact, you could say that there is nothing at all uncertain about the electron's spin: It has a definite spin of +1/2 along the axis ##\vec{S}## satisfying
##S_z = \frac{1}{2} (|\alpha|^2 - |\beta|^2)##
##S_x = \frac{1}{2} (\alpha \beta^* + \alpha^* \beta)##
##S_z = \frac{i}{2} (\alpha \beta^* - \alpha^* \beta)##
So now put that electron through a Stern-Gerlach device, so that electrons that are spin-up in the z-direction are deflected to the left, to make a dot on the left side of a photographic plate, and electrons that are spin-down in the z-direction make a dot on the right side.
Most people would say that now probabilities come into play. There will be a probability of ##|\alpha|^2## of a dot on the left, and a probability of ##|\beta|^2## of a dot on the right.
But why? Presumably, Stern-Gerlach devices and photographic plates are made up of electrons and protons and photons and neutrons. Each of these constituents is like the original electron, in having a quantum state. So why isn't it the case for this huge system that there are no probabilities until someone measures ITS state? (And whatever you use to measure its state, you can ask why isn't it described by a quantum state, requiring yet another measurement to give probabilities.)
The measurement problem is basically why probabilities apply to measurements (which presumably are just quantum mechanical interactions involving a huge number of particles) but not to interactions involving a small number of particles (one or two or three electrons, for example)?