Coulomb force and charge equilibrium on the xy-plane

AI Thread Summary
The discussion centers on determining the location and magnitude of a third charge, Q, in a system with two point charges, q and 4q, on the xy-plane, ensuring that the total force on each charge is zero. The user calculated R as (2r1 + r2)/3 and Q as 4q/9, but these values do not match the provided options. It was pointed out that Q must have a negative value to attract the other charges, preventing them from being pushed away. The user is encouraged to share their calculations for further verification. The conclusion emphasizes the importance of correctly applying Coulomb's law to find the equilibrium condition.
PRASHANT KUMAR
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Homework Statement


Two point charges q and 4q are located at r1 and r2, respectively, on the xy- plane. The magnitude Q and location R of a third charge to be places on the plane such that the total force on each of the three charges vanishes, are?

first i plotted the problem on the xy coordinate system and then the position vectors of two charges q and 4q as r1 and r2 and then i kept the charge Q at R and then i calculated the sum of forces on the charge q by the two other charges and equated to zero. And again using coulomb force relation i equated the sum of forces on charge Q by q and 4q then i calculated the values of Q and R

i am getting R=(2r1+r2)/3 and Q= 4q/9 but the options are
  1. Q= -4q/9 and R= (2r1+r2)/3
  2. Q= -4q/5 and R= (r1+2r2)/3
  3. Q= -4q/25 and R= (16r1+r2)/17^(1/2)
4.Q= -9q/4 and R =(r1 + 2r2)/3

in calculating the above problem i was equating the magnitude of the forces .
So, is my answer correct or not?
if not then how to calculate that ?
 
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PRASHANT KUMAR said:
am getting R=(2r1+r2)/3 and Q= 4q/9
It clearly cannot have the same sign as q. That would subject q and 4q to net forces pushing them away from Q. Please post your working.
 
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