Coulomb potential removes the degnerecay of states

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eman2009
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Hi every one this is the first time in this wonderful forum :)

and i have a question i hope i find an answer ?

how can the additiona of a smalll (c/r square)term to the coulomb potential removes the degnerecay of states with different (small) L. (quantum defect)?

:confused:

thanks
 
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generally, a perturbation lifts the degeneracy.

The additional factor 1/r^2 is related to the spin-orbit interaction, which will have a 1/r^2 dependence [tex]\frac{1}{r}\frac{dV_C}{dr}(vec{L}\cdot \vec{S})[/tex] The derivative of the couloumb potential is 1/r^2 and L is proportional to r
 


I suggest that you refer to textbook.
(For example, Griffiths chapter 6)

By using perturbation theory, you can calculate approximate energy and fine slit of energy level on same value of L^2.

<1/r^2> can be calculated and it's value contains n,l so you may take good quantum number n,l ...