Coulomb's Law: Examining Forces and Charges

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Doubling one of the charges in Coulomb's Law will result in the force also doubling. If both charges are halved, the force will decrease to a quarter of its original value. Tripling the distance between the charges will reduce the force to one-ninth, while halving the distance will increase the force by a factor of four. If one charge is tripled and the distance is doubled, the force will increase by a factor of 1.5. To determine the number of excess electrons on a charged particle, divide the total charge by the charge of a single electron.
UrbanXrisis
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questions relate to coulomb's law.

What will happen the to force if:

one of the charge was doubled. (ex.q1 was doubled)
I think that the force would double as well right?

What if q1 and q2 were cut in half?

the distance is tripled?

the distance is cut in half? How do I figure this out?

What if q1 was tripped and the distance doubled?

Thanks
 
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See my answer on your other thread.
 
TO do this you need to look at the form of coulombs law. It is given by:
<br /> F_c=\frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}<br />
where r is the separation distance btw the paticles and q1 and q2 are the charges of the particles in question. By looking aT what should happen to F when you say double q1 you should be able to figure it all out
 
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