Cp & Cv Values: Example Problem 11.1 Explained

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williamcarter
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Hello, I tried attempting the following example problem 11.1(please see below), however I don't quite get from where they got cp=1.00 and cv=0.717?
I know that Q=m*cp*delta T=> cp=Q/(m*delta T)
Q=n*cv*delta T=>cv=Q/(n*deltaT)

Problem statement
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Their solution:
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How did they manage to get for cp=1.00 and cv=0.717?

Thank you
 
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Chestermiller said:
(3.5)(8.314)/29=1.00
Thank you , but how did you get these numbers from? They are not given in the statement of the problem.
What about cv?
 
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