Cross sectional area (NOT A QUESTION)

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SUMMARY

The discussion provides a comprehensive overview of cross-sectional areas, defining it as the area of a flat, two-dimensional representation of a three-dimensional object. For a cylinder, the cross-sectional area is the area of its circular base, calculated as πr². For a sphere, the cross-sectional area is also a circle with the same radius, while for an ellipsoid, it is represented by an ellipse with the long (a) and short (b) axes, calculated as πab. The discussion also notes that for an oblate ellipsoid like Earth, the cross-sectional area simplifies to πr².

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moonman239
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Just for those who don't know a thing about cross sectional areas, I thought I'd explain.

A cross sectional area describes the area of a flat (2-dimensional) representation of a 3-dimensional object. So if I cut a cylinder, instead of seeing two circles, I see four circles (unless there are other circles in my environment). The cross-sectional area is the area of either of the two circles.

For a cylinder or right solid, the cross-sectional area is the area of the base.
For a sphere, the cross sectional area is the area of a circle with the same radius (pi*r2).
For an ellipsoid, the cross sectional area is the area of an ellipse with the same long (a) and short (b) axes (pi*ab).
 
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I don't know what to say. Thanks for sharing?
 
lol at landau's response
 
Oh, for an oblate ellipsoid (such as Earth), where lines of latitude are circular, the area is simply pi*(r^2)
 

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