xeon123
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I was looking to a video about cumulative distribution function () and he show the following function:\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | 1/4, 0 \leq x \leq1 \\<br />
f(x) =<(x^3)/5, 1 \leq x \leq 2 \\<br />
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |0, otherwise.
At minute 8:45, he presents the cumulative distribution as:<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | 0, x \leq 0 \\<br /> F(x) = < \frac{1}{4}x, 0 \leq x \leq 1 \\<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \frac{1}{20}(x^4+4), 1 \leq x \leq 2 \\<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | 1, \ x \geq 2<br />
I don't understand why F(x) is 1 for x \geq 2, if f(x) is 0, otherwise. Why?BTW, I hope that that my functions are legibles, because I don't know how to put big curly brackets.
At minute 8:45, he presents the cumulative distribution as:<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | 0, x \leq 0 \\<br /> F(x) = < \frac{1}{4}x, 0 \leq x \leq 1 \\<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \frac{1}{20}(x^4+4), 1 \leq x \leq 2 \\<br /> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | 1, \ x \geq 2<br />
I don't understand why F(x) is 1 for x \geq 2, if f(x) is 0, otherwise. Why?BTW, I hope that that my functions are legibles, because I don't know how to put big curly brackets.
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