Cumulative distribution function question

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SUMMARY

The discussion focuses on calculating the cumulative distribution function (CDF) for a random variable Y derived from rolling a die, where Y = X^2 and X represents the die outcome. The user correctly identifies that for Y = 1, the CDF can be computed as P(Y ≤ 1) = P(X ≤ 1) since Y is defined as the square of X. Additionally, the user seeks assistance in evaluating probabilities for a standard normal distribution, specifically P(X ≤ -5), P(-2 ≤ X ≤ 7), and P(X ≥ 3), using the standard normal distribution function ϕ.

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sneaky666
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consider rolling a die.
S= {1,2,3,4,5,6}
P(s)=1/6 for all s in S
X= number on die so that X(s)=s for all s in S
Y= X^2
compute the cumulative distribution function Fy(y) = P(Y<=y), for all y in the set of real numbers.

My guess
for Y=1 i get
P(-inf<y<=1)=P(Y<=1)-P(Y<-inf)=Fx(1)-Fx(-inf)
= Fx(1)-0
= Fx(1)

Is this all I have to do for Y=1, or do I have to integrate, or is there anything wrong?
 
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EDIT: ok i figured it out but i need help on this one.

Let X~N(0,1) . Compute each in terms of function ϕ.
And evaluate it numerically.

P(X<=-5)
P(-2<=X<=7)
P(X>=3)

for the first one i get
ϕ(-5)

But how do i evaluate it?
 

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