Cumulative distribution function question

AI Thread Summary
The discussion revolves around calculating the cumulative distribution function (CDF) for a random variable Y derived from rolling a die, where Y equals the square of the die's outcome. The user initially computes the CDF for Y=1 and seeks clarification on whether further integration is necessary. They later shift focus to evaluating probabilities for a standard normal distribution, specifically asking for help in computing P(X<=-5), P(-2<=X<=7), and P(X>=3) in terms of the standard normal distribution function ϕ. The user expresses uncertainty about how to numerically evaluate these probabilities. The thread highlights the transition from discrete to continuous probability distributions and the application of the normal distribution in statistical calculations.
sneaky666
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consider rolling a die.
S= {1,2,3,4,5,6}
P(s)=1/6 for all s in S
X= number on die so that X(s)=s for all s in S
Y= X^2
compute the cumulative distribution function Fy(y) = P(Y<=y), for all y in the set of real numbers.

My guess
for Y=1 i get
P(-inf<y<=1)=P(Y<=1)-P(Y<-inf)=Fx(1)-Fx(-inf)
= Fx(1)-0
= Fx(1)

Is this all I have to do for Y=1, or do I have to integrate, or is there anything wrong?
 
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EDIT: ok i figured it out but i need help on this one.

Let X~N(0,1) . Compute each in terms of function ϕ.
And evaluate it numerically.

P(X<=-5)
P(-2<=X<=7)
P(X>=3)

for the first one i get
ϕ(-5)

But how do i evaluate it?
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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