I Curiosity: there exists the exponential integral?

Ssnow
Science Advisor
Messages
573
Reaction score
182
Hi, my question regard the possibility to consider a generalization on the product integral (of type II). The product integral is defined in analogy to the definite integral where instead the limit of a sum there is a limit of a product and, instead the multiplication by ##dx## there is the power of ##dx##, in other terms:

\prod_{a}^{b}f(x)^{dx}\,=\, \lim_{n\rightarrow +\infty} \prod_{i=1}^{n}f(x_{i})^{\Delta x_{i}}

considering a reasonable partition of the interval ##(a,b)##, (you can find references on wiki with a lot of details for product integral of type II or others on the web).
The question is, there is a generalization of this by "analogy'' using exponentiation and tetration function (extended to real heights), this will be formally:

EXP_{a}^{b}f(x)\uparrow \uparrow dx\,=\, \lim_{n\rightarrow +\infty} \left(f(x_{i})\uparrow \uparrow\Delta x_{i}\right)^{\left(f(x_{i})\uparrow \uparrow\Delta x_{i}\right)^{(\cdots)}}\ \ (n-times)

where ##\uparrow\uparrow## is the tetration function ?
Ssnow
 
Physics news on Phys.org
Ssnow said:
Hi, my question regard the possibility to consider a generalization on the product integral (of type II). The product integral is defined in analogy to the definite integral where instead the limit of a sum there is a limit of a product and, instead the multiplication by dx there is the power of dx, in other terms:

∏abf(x)dx=limn→+∞∏i=1nf(xi)Δxi

considering a reasonable partition of the interval (a,b), (you can find references on wiki with a lot of details for product integral of type II or others on the web).
Say f(x)>0, it would be
e^{\int_a^b \log f(x)dx}

I am not sure of the definition of ##\uparrow\uparrow c## where c is not integer. Could you show it to me ?
 
Last edited:
anuttarasammyak said:
Say f(x)>0, it would be
e^{\int_a^b \log f(x)dx}
This is another form for the product integral ...
 

Similar threads

Replies
16
Views
4K
Replies
7
Views
3K
Replies
3
Views
2K
Replies
14
Views
3K
Replies
9
Views
2K
Back
Top