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Curl about an elipse. Line integral of vector field

  1. Apr 5, 2008 #1
    1. The problem statement, all variables and given/known data
    It can be shown that the line integral of F = xj around a closed curve in the xy - plane, oriented as in Green's Theorem, measures the area of the region enclosed by the curve. (You should verify this.)

    Use this result to calculate the area within the region of the parameterized curve given below.
    x = acos(t) y= bsin(t) for 0<t<2pi

    3. The attempt at a solution
    I tried integrating an ellipse using cartesian limits, but ended up with zero under a radical. I can't think of a way to integrate this in terms of t, since our book has no such example. Using Green's theorem does not put the a and b constants anywhere in the equation, which confuses me...
  2. jcsd
  3. Apr 6, 2008 #2


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    Well, you certainly have me confused. It is pretty well known that the area of an ellipse [itex]x^2/a^2+ y^2/b^2= 1[/itex] is [itex]\pi ab[/itex]. Since you haven't shown any work at all, I can't say where you went wrong.

    And I can't believe that your text has no examples at all of integrating a vector function [itex]\vec{F}(t)[/itex] over a curve given by the parametric equations [itex]s(t)= x(t)\vec{i}+ y(t)\vec{j}[/itex]. The integral is simply [itex]\int \vec{F}(t)\cdot \vec{ds}(t)[/itex].

    In this case, [itex]\vec{ds}= (-a sin(t)\vec{i}+ b cos(t)\vec{j})dt[/itex] and [itex]\vec{F}(t)= x\vec{j}= a cos(t)\vec{j}[/itex]. Take the dot product of those two functions and integrate from t= 0 to [itex]t= 2\pi[/itex].

    As for Green's theorem, it says
    [tex]{\int\int}{\Omega}\left[\frac{\partial Q(x,y)}{\partial x}- \frac{\partial P(x,y)}{\partial y}\right] dx dy= \int_C P(x,y)dx+ Q(x,y)dy[/itex]
    In this case, the function you are integrating around the circumference of the ellipse is just [itex]x\vec{j}[/itex] so P= 0 and Q= x. That means that
    [tex]\frac{\partial Q}{\partial x}= 1[/tex]
    so you are integrating 1 over the area of the ellipse Of course, that gives the area! a and b appear in the integral on the right when you put in the limits of integration.
  4. Apr 6, 2008 #3
    Thanks for the excellent reply. I did some integrating that was similar, but did not think that a line integral could be expressed in terms of t! There is no such example in our book, although I saw one such integral in a packet that our teacher handed us.

    Unfortunately, our book does not even have an example of the line integral of a circle!
  5. Apr 6, 2008 #4
    I worked it out and managed to get it. Such a simple answer, but so elusive.
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