Current Carrying Wires-No force b/t them?

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Two parallel current-carrying wires should exert attractive forces on each other, while anti-parallel wires should repel, according to Faraday's law. However, an experiment involving a vacuum cleaner's power cord showed no observable force when the wires were configured in both parallel and anti-parallel arrangements. The discussion revealed that the net current through the wire was effectively zero, as the current flowing into the load was canceled by the current returning, which explained the lack of force. Questions arose regarding the safety and methodology of the experiment, particularly about accessing the wires and measuring the force. Ultimately, the simplicity of the explanation highlighted the importance of understanding current flow in power cords.
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Current Carrying Wires--No force b/t them?

Faraday's law predicts that two current-carrying wires, when placed parallel to each other, will exert an attractive force on each other. Conversely, two wires that are placed anti-parallel to each other will exert a repulsive force on each other.

While I was vacuuming my apartment today, I decided to test this phenomenon. I folded the wire into two parts such that one part of the wire was touching the other, with its current flowing in the opposite direction. The result? Nothing. According to Faraday's law, however, the wires should have exerted an attractive force on each other.

I then folded the wires such that one part was touching the other, with its current flowing in the same direction. The result? Again, nothing. But according to Faraday's law, the wires should have exerted a repulsive force on each other.

How can I make sense of this result?

Of course, the electrical input is AC 60hz, not DC. But this shouldn't matter. If the wires are parallel to each other, then on the positive half cycle, both currents will be in the same direction, and the wires will exert a repulsive force on each other. Likewise when the input is on its negative half cycle. The frequency of the input would not seem to make any difference.

Maybe the rubber coating around the wire stifles the magnetic field created by the current flow? I've never read anything that would suggest this.

Any comments would be greatly appreciated.
 
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brianparks,

Hint: Suppose your vacuum's drawing 5 amps, what's the net current through the wire? Actually, it's a cord (that's another hint!).
 
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Doh! One cord, two wires inside, one with current going into the load, the other with current coming out. So they cancel. It never occurred to me that the answer was so simple--and that the question was so stupid!

Anyway, thanks for clearing that up :biggrin:
 
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brianparks said:
It never occurred to me that the answer was so simple--and that the question was so stupid!
Whoa, now, wait a second. Can you explain further. I didn't understand your experiment.

What does your experiment have to do with vacuuming the apartment?

What wires are you talking about (the ones in the power cord)? Did you cut up the power cord to access the wires (not all that safe :rolleyes: )? Did you just consider the power cord as a wire?

How did you measure the force? (This is my most curious question. If you've ever done this experiment in a controlled lab environment, or even just calculate it, you'll know that the force is absolutely miniscule at a separation on the order of millimeters at a current on the order of amps. I.e. separation of 1 mm between two lengths of wire a foot long carrying 10 A gives you a magnetic force about equal to the weight of a single pea).
 
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I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...
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