Current density of a filamentary loop

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SUMMARY

The discussion focuses on the derivation of the current density of a filamentary loop, specifically a loop of radius 'a' located at 'z=h' carrying a current 'I'. The current density for a small segment of the loop is expressed as j=Iad\phi\delta(\vec{r}-\vec{r_0}), where r_0=a\hat{\rho}+\phi\hat{\phi}+h\hat{z}. The use of Dirac delta functions in this context is crucial for representing the current density at a specific point in space, although the user expresses confusion regarding the interpretation of this expression as "current per unit area perpendicular to flow".

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Hi,

I'm trying to wrap my head around the derivation of the current density of a filamentary loop. On the face of it, the result seems obvious since it involves Dirac delta functions, but it's the rest of the formulation I don't quite follow.

The derivation begins by considering a loop of radius a at z=h carrying a current I. Considering a small portion of the loop dS, a quantity [tex]Id\vec{S}=Iad\phi\hat{\phi}[/tex]. Already I'm not sure why we're considering the current times the length of the element of the loop. In any case, the current density of that small element can be written (apparently) as [tex]\vec{j}=Iad\phi\delta(\vec{r}-\vec{r_0})[/tex] where [tex]r_0=a\hat{\rho}+\phi\hat{\phi}+h\hat{z}[/tex]. This is where I'm hung so far. Can someone explain what's going on here to me? I know what a current density is, and I know what the purpose of the delta function is. I don't see this as an expression of "current per unit area perpendicular to flow", though.

Thanks.
 
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I should probably clarify that the loop is at x=y=0, and that [tex]\rho[/tex], [tex]\phi[/tex], and z are cylindrical coordinates.
 

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