Outside the origin circular loop current density

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Discussion Overview

The discussion revolves around deriving the current density for a circular loop of radius a that is displaced along the y-axis in spherical coordinates. Participants explore the mathematical formulation and relationships involved in this scenario, addressing both theoretical and technical aspects of the problem.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents an initial expression for the current density of a circular loop at the origin but seeks to modify it for a loop displaced by a distance c along the y-axis.
  • Multiple participants express confusion regarding the units of the proposed current density and the relationship between the parameters a, c, and r, suggesting that the formulation may be incorrect.
  • A participant corrects their earlier expression for current density, providing a new formulation and attempting to clarify their original question with an accompanying image.
  • Another participant suggests a method to derive the desired current density by translating the origin-centered solution into Cartesian coordinates before converting back to spherical coordinates.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct formulation of the current density. There are competing views regarding the initial expression and its validity, as well as ongoing confusion about the parameters involved.

Contextual Notes

There are unresolved issues regarding the definitions and relationships between the variables a, c, and r, as well as the implications of the units used in the current density formulation.

Mr. Rho
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Hi, I'm trying to write the current density for such circular loop in spherical coordinates. For a circular loop of radius a that lies in the XY plane at the origin, the current density it's simply:

\mathbf{J}= \frac{I}{2\pi\sin\theta}\delta(\theta-\frac{\pi}{2})\frac{\delta(r-a)}{a}\hat{\phi}​

I want the current density of the circular loop of radius a displaced a distance c towards the y axis.

Any suggestions?
 
Last edited:
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I can't make sense of this. Your units don't balance. What is the relationship between a, c, and r? Could you try again?
 
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stedwards said:
I can't make sense of this. Your units don't balance. What is the relationship between a, c, and r? Could you try again?
Sorry I wrote the equation wrong, just fixed it. I'm using this kind of spherical coordinates:

250px-Spherical_polar.png
 
No, really. Think about it a bit and restate the entire question. 'cuse, now current and current density have the same units, and nobody knows what ##c## is. I'd sleep on it.
 
stedwards said:
No, really. Think about it a bit and restate the entire question. 'cuse, now current and current density have the same units, and nobody knows what ##c## is. I'd sleep on it.

I don't know what I was thinking, the correct current density is:

\mathbf{J}=I\delta(\theta-\frac{\pi}{2})\frac{\delta(r-a)}{a}\hat{\phi} = I\sin\theta\delta(\cos\theta)\frac{\delta(r-a)}{a}\hat{\phi}​

it satisfies I=\int\mathbf{J}\cdot{d\mathbf{S}}=\int_{0}^{\pi}\int_{0}^{\infty}\mathbf{J}\cdot{\hat{\phi}}rdrd\theta, where \mathbf{S} is a surface perpendicular to the current direction.

Sorry for not making myself clear for what I'm asking. I hope this image makes things clear:

Untitled.png
The current density I present is case (i) and the current density I need is case (ii).
 
To begin with, take the origin-centered solution for a circle of radius ##a##, change to Cartesian coordinates, translate to the right (##x \leftarrow x' = x + c##), then back to spherical coordinates.

It will give the equation for the current path you want.
 
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