Are you talking about the sphere of radius R in three dimensions?
Start by writing out x, y, and z in spherical coordinates with \rho taken as the constant R:
x= Rcos(\theta)sin(\phi)
y= Rsin(\theta)sin(\phi)
z= R cos(\phi)
Calculate the differentials:
dx= - R sin(\theta)sin(\phi)d\theta+ Rcos(\theta)cos(\phi)d\phi
dy= R cos(\theta)sin(\phi)d\theta+ Rsin(\theta)cos(\phi)d\phi
dz= -R sin(\phi)d\phi
Find ds^2= dx^2+ dy^2+ dz^2 in terms of spherical coordinates:
dx^2= R^2 sin^2(\theta)sin^2(\phi)d\theta^2- 2R^2sin(\theta)cos(\theta)sin(\phi)cos(\phi)d\theta d\phi+ R^2cos^2(\theta)cos^2(\phi)d\phi^2
dy^2= R^2cos^2(\theta)sin^2(\phi)d\theta^2+ 2R^2sin(\theta)cos(\theta)sin(\phi)cos(\phi)d\thetad\phi+ R^2sin^2(\theta)cos^2(\phi)d\phi^2
dz^2= R^2 sin^2(\phi)d\phi^2
Adding those
ds^2= R^2sin^2(\phi)d\theta^2+ R^2 d\phi^2
which gives us the metric tensor:
g_{ij}= \begin{pmatrix}R^2sin^2(\phi) & 0 \\ 0 & R^2 \end{pmatrix}
You can calculate g^{ij}, the Clebsh-Gordon coefficients, and the curvature tensor from that.