(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A particle moves along the curve of intersection of shapes y = -x^{2}and z = x^{2}in the direction in which x increases. At the instant when the particle is at the point P(1,-1,1), its speed is 9cm/s and that speed is increasing at a rate of 3cm/s^{2}. Find the velocity and acceleration of the particle at that instant

2. Relevant equations

||[itex]\vec{v}[/itex]|| = 9

Derivative of ||[itex]\vec{v}[/itex]|| = 3

[itex]\vec{v}[/itex] = [itex]\vec{R'}[/itex] where [itex]\vec{R}[/itex] is the curve.

3. The attempt at a solution

I tried Googling it but I could not find a definite answer to my question. What I want to know is how do I find the [itex]\vec{R}[/itex] (curve defined by intersections). I have never encountered a similar problem before and I don't really know how to approach it. If you could hint me the right direction, it would be greatly appreciated.

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# Curve of intersection of 2 functions

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