D/dt of <y1|y2> =0 quantum physics

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SUMMARY

The discussion focuses on confirming that the time derivative of the integral of the product of two wavefunctions, Y1 and Y2, is zero, expressed mathematically as d/dt ∫ Y1* Y2 = 0. The user applies the product rule and the Time-Dependent Schrödinger Equation (TDSE) to derive the expression (i/ħ) [ ∫ H* Y1* Y2 - ∫ Y1* H Y2 ]. The challenge lies in further simplifying this expression, particularly regarding the use of commutator relations due to the operator's position in the equation. Y1 and Y2 are defined as wavefunctions dependent on spatial and temporal variables.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically wavefunctions.
  • Familiarity with the Time-Dependent Schrödinger Equation (TDSE).
  • Knowledge of product rule in calculus.
  • Basic concepts of quantum operators and commutation relations.
NEXT STEPS
  • Study the implications of the Time-Dependent Schrödinger Equation (TDSE) on wavefunction behavior.
  • Research the properties of commutators in quantum mechanics.
  • Explore advanced calculus techniques related to integrals of products of functions.
  • Investigate the role of Hamiltonians in quantum mechanics and their effect on wavefunctions.
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Students and researchers in quantum physics, particularly those working on wavefunction analysis and time evolution in quantum systems.

Chronos000
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Homework Statement




I have to confirm that d/dt \int Y1* Y2 = 0


So far I have used the product rule to get two expressions.

Then I have used the TDSE to replace dY/dt and dY*/dt. I end up with the line:

(i/\hbar) [ \int H* Y1* Y2 - \int Y1* H Y2 ]

from here I'm not sure where to go. I thought about using the commuator relation but I don't think i can since the operator is at the start of the expression in expression 1.
 
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What's Y1 and Y2?
 
they are just wavefunctions which depend on x and t
 

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