Damped Driven Harmonic Oscillator.

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SUMMARY

The discussion centers on the analysis of a damped driven harmonic oscillator with a mass of 0.5 kg, stiffness of 100 N/m, and mechanical resistance of 1.4 kg/s, driven by a sinusoidal force of amplitude 2 N. Participants confirm the use of the equations for displacement and speed amplitude, specifically A(w) and the phase angle Φ, derived from the differential equation governing the system. A key point of contention is the interpretation of the phase angle between speed and displacement, with consensus suggesting a potential misprint in the homework statement regarding the phase shift. Participants agree on addressing this misprint in their solutions to clarify their rationale.

PREREQUISITES
  • Understanding of harmonic oscillators and their equations of motion
  • Familiarity with sinusoidal driving forces and their effects on oscillatory systems
  • Knowledge of phase angles in oscillatory motion
  • Ability to differentiate functions to find speed from displacement
NEXT STEPS
  • Explore the concept of phase shifts in driven harmonic oscillators
  • Learn about the implications of damping in oscillatory systems
  • Investigate the mathematical derivation of speed amplitude in damped systems
  • Review common misprints and ambiguities in physics homework problems
USEFUL FOR

Students studying classical mechanics, particularly those focusing on oscillatory motion, as well as educators looking for examples of common misunderstandings in homework assignments related to harmonic oscillators.

vkumar1403
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Homework Statement


An oscillator with mass 0.5 kg, stiffness 100 N/m, and mechanical resistance 1.4 kg/s is driven by a sinusoidal force of amplitude 2 N. Plot the speed amplitude and the phase angle between the displacement and speed as a function of the driving frequency and find the frequencies for which the phase angle for which the angle is 45 deg.

Homework Equations

The Attempt at a Solution


Using the general form of the solution:
x(t) = A(w) sin(wt-Φ)
where Φ=atan(2wp/(w_0^2-w^2))
A(w) = (F/m)/((w_0^2-w^2)^2 + (2wp)^2)^0.5

I am positive the above equations are correct and come from the differential equation for this case.

Now, u(t) [speed] = d x(t)/dt.
= w*A(w)*cos(wt-Φ)
=w*A(w)*sin(wt-Φ+pi/2)

My question: Now the speed amplitude, I believe, is wA(w). Won't the phase angle between the displacement and velocity always be pi/2 irrespective of w?[/B]
 
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Yes, but this is not the phase shift. The phase shift is the phase between the driving force and the position, i.e., φ.
 
Orodruin said:
Yes, but this is not the phase shift. The phase shift is the phase between the driving force and the position, i.e., φ.
I agree but the question says the phase between the speed and the displacement. Am I interpreting this wrong?
 
vkumar1403 said:
I agree but the question says the phase between the speed and the displacement. Am I interpreting this wrong?
It is very likely a misprint.
 
Orodruin said:
It is very likely a misprint.
Thanks! I'm going to quote this as a misprint in my solution with the explanation of my rationale. Hopefully, that is good enough for my professor
 

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