Damped Oscillations in an RLC circuit

[electrohau5]

Homework Statement

A single loop circuit consists of a 7.2 ohm resistor, a 11.9 H inductor, and a 3.4*10^-6 F capacitor. Initially the Capacitor has a charge of 6.3*10^-6 C and the current is zero. Find the charge on the capacitor N complete cycles later for N=5.

Homework Equations

2. Homework Equations
q=Qe^(-Rt/2L)cos(wt + p), where p is the phase constant and w is the angular frequency.

The Attempt at a Solution

I have already found angular frequency to be 157.2122, but how do I relate this to time it takes to make 5 cycles? I do not fully understand the definition of w.
(the idea of angular frequency has always been quite confusing to me as I have not yet taken mechanics and am doing E&M first)

 

[ehild]

See:

http://scienceworld.wolfram.com/physics/AngularFrequency.html

ehild

 

[rude man]

Homework Statement

A single loop circuit consists of a 7.2 ohm resistor, a 11.9 H inductor, and a 3.4*10^-6 F capacitor. Initially the Capacitor has a charge of 6.3*10^-6 C and the current is zero. Find the charge on the capacitor N complete cycles later for N=5.

Homework Equations

2. Homework Equations
q=Qe^(-Rt/2L)cos(wt + p), where p is the phase constant and w is the angular frequency.

The Attempt at a Solution

I have already found angular frequency to be 157.2122, but how do I relate this to time it takes to make 5 cycles? I do not fully understand the definition of w.
(the idea of angular frequency has always been quite confusing to me as I have not yet taken mechanics and am doing E&M first)

Angular frequency is radians per second. So 1 rotation per second is 2pi radians per second. Etc.

If you know w which = 2pi * f, then period T = 1/f as you know I'm sure.

 

[electrohau5]

See:

http://scienceworld.wolfram.com/physics/AngularFrequency.html

ehild

would the time it takes be equal to 5 times the period, so 10pi/w?

 

[ehild]

would the time it takes be equal to 5 times the period, so 10pi/w?

Yes.

ehild

 

[rude man]

would the time it takes be equal to 5 times the period, so 10pi/w?

Yes again.