Data Management: Premutations Problem With identical Items

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The discussion revolves around calculating the number of ways to fill four positions among ten students, considering the Norman twins as indistinguishable. The initial calculation using permutations gives 5040 ways to select the positions. However, the challenge lies in accounting for the twins' ability to switch roles, which complicates the total count. The poster suggests breaking the problem into three cases based on the twins' involvement in the positions. Ultimately, there is uncertainty about the textbook's answer of 4032, leading to doubts about either the interpretation of the problem or the accuracy of the provided solution.
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Homework Statement


Ten students have been nominated for positions of secretary, treasurer, social convenor, and fundraising chair. In how many ways can these positions be filled if the Norman twins are running and plan to switch positions on occasion for fun since no one can tell them apart?

txt book answer:4032

Homework Equations


n! factorials

nPr= n!/(n-r)! premutations

n!/(a!b!c!...) premutations with identical items


The Attempt at a Solution


10P4=5040 totals ways nominations can be picked

i don't know how to find the number of ways twins can be picked/ answer
 
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I guess we are to treat the twins as indistinguishable. So try breaking the problem up into three cases:
(1) No twin holds a position;
(2) Exactly one twin holds a position;
(3) Both twins hold positions.

I think I should warn you that I don't get the book answer. So I'm going to stick my neck out and say that the book is wrong. Of course, it may be that I have misinterpreted the problem. I do that a lot.
 
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