Dealing with exponent laws (2 simple questions in one thread)

AI Thread Summary
The discussion revolves around simplifying the expression 6^1 + 6^-1 / 6^1 - 6^-1 and understanding exponent laws. Participants suggest combining the fraction by multiplying both the numerator and denominator by 6 to eliminate negative exponents. For the comparison of 20^100 and 400^20, it is noted that 400 can be expressed as 20^2, leading to the conclusion that 400^20 equals 20^40, thus establishing that 20^100 is greater. The conversation highlights the importance of recognizing base relationships in exponent comparisons. Overall, the thread emphasizes the application of exponent laws in simplifying expressions and making comparisons.
mike_302
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Homework Statement



6^1+6^-1 / 6^1-6^-1 (Question is to evaluate that, but I am going to venture to guess that we are supposed to somehow simplify the question a lot further. We just finished learning all the exponent laws)


Explain how you can tell which is bigger without evaluating: 20^100 or 400^20 ?



Have not been able to evaluate at all.
 
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x^-1 = 1/x

From there, you can finish it a number of ways. I'd probably just combine the fraction & then divide the whole thing to get a fraction result.

To find which is larger, they both start with 6, & either add or subtract x^-1. If you add a positive number to 6 or subtract a negative number, the positive number will be larger.
 
OH! haha. The second part with "which is bigger" is a whole differnt question. Sorry I didn't make that clear :P .

Anyways, since only the fist question was answered with accuracy here, I would like to discus that quickly. How do you combine the fraction like you say? That is where I am getting mixed up: Rearranging to get all positive exponents.
 
mike_302 said:

Homework Statement



6^1+6^-1 / 6^1-6^-1 (Question is to evaluate that, but I am going to venture to guess that we are supposed to somehow simplify the question a lot further. We just finished learning all the exponent laws)
\frac{6+ 6^{-1}}{6- 6^{-1}}
Multiply both numerator and denominator by 6.


Explain how you can tell which is bigger without evaluating: 20^100 or 400^20 ?
20= 2^2(5) so 20^{100}= 2^{200}(5^{100}). 400= 40(100)= (8*5)(4*25)= 2^5(5^3) so 400^{20}= 2^{100}(5^{60})
Can you compare those?



Have not been able to evaluate at all.
 
ahhh! Yes, I see for both now. I understand the first one and well... The second one, I get the idea of making them both have similar bases but how you did it would take a little more concentration on my behalf. I will do that after posting this but I must thank you for your work.
 
HallsofIvy said:
20= 2^2(5) so 20^{100}= 2^{200}(5^{100}). 400= 40(100)= (8*5)(4*25)= 2^5(5^3) so 400^{20}= 2^{100}(5^{60})
Can you compare those?

Actually, it is easier to solve if you see that 400 = 20^2. from which you get that 400^{20} = 20^{2 * 20} = 20^{40} and of course 20^{100} > 20^{40}.

EDIT: It's a property of exponents that (a^b)^c = a^{bc}
 
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You're right. I understand that now, no problem. Thanks for your help as well! :)
 
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