Decay of Lightest Supersymmetric electrically charged particle

[JustinLevy]

If we assume R-parity like in MSSM, shouldn't the lightest supersymmetric electrically charged particle be fairly stable? My question is two fold:

1] if we assume R-parity and supersymmetry (at least at high energies) is there a fairly model independent (ie. no details of how it "broke") way to get the lifetime of this particle? It seems like it would have to happen via the weak force, so maybe dimensional analysis used appropriately can give an order of magnitude somehow?

2] Shouldn't the reverse process already have been seen? Can we place decent constraints by noticing that no long lived electrically charged particles come out of "weak force" scattering of high energy protons off of dark matter that is everywhere?

Basically, we wouldn't need to have enough energy to create the particles outright, but have the energy equal to the gap between the dark matter particle and the first charged state. It seems like we should be able to probe supersymmetry before even getting to the supersymmetric scale.

 

[lpetrich]

If the particles obey R parity, then a Lightest Supersymmetric Particle will not decay.

The only way it can disappear is to run into another supersymmetric particle.

But this LSP is usually expected to be neutral, meaning that the lighest charged one will be more massive than it. That charged one will thus decay into an odd number of supersymmetric particles and likely also some ordinary particles.