Deceleration falling into a harness

Click For Summary
SUMMARY

The discussion centers on calculating the forces experienced by a person falling 600mm without shock-absorbing capabilities, which is commonly accepted to generate a force of 6kN. The participant, a Rope-Access tutor, uses the equation Vf² = Vi² + 2ad to determine the velocity before impact, arriving at 3.431 m/s. They seek clarification on the deceleration process and whether factors like body mass and harness elasticity affect the calculations. Additionally, they question the validity of using the equation E = mgh to estimate potential energy and its conversion to force in kilonewtons.

PREREQUISITES
  • Understanding of basic physics concepts, including kinematics and forces.
  • Familiarity with equations of motion, specifically Vf² = Vi² + 2ad and F = ma.
  • Knowledge of energy concepts, particularly potential energy calculations using E = mgh.
  • Basic grasp of the effects of elasticity in materials, especially in safety harnesses.
NEXT STEPS
  • Research the effects of harness elasticity on fall dynamics in rope-access scenarios.
  • Explore advanced kinematic equations to better understand deceleration calculations.
  • Investigate the relationship between body mass and impact forces in fall scenarios.
  • Learn about energy transfer during falls and how to accurately convert potential energy to force.
USEFUL FOR

Rope-access professionals, safety engineers, and anyone involved in fall protection and physics applications in safety equipment design.

wikithellama
Messages
1
Reaction score
0
Hi!

This isn't exactly a homework question - I am not studying physics (though I was good at high school physics once-upon-a-time) it is just something that I am interested in and Google isn't being very cooperative. If this is in the wrong place, please let me know - I thought since it is such simple equations it belongs in this section :)

I also may be over-complicating this somewhat and I am a complete n00b so please bear with me...

I am a Rope-Access tutor and it is "common knowledge" in the industry that a 600mm fall on a system with no shock-absorbing capabilities will generate a force of 6kN on the human body.

Now with the remnants of high school physics that I have, I believe that this would depend on the mass of the "victim" and on the elasticity of the harness etc... (I am thinking that I am in a little over my head)

I am not someone who takes things for granted so I am trying to work it out for myself.
I was going to ignore the elasticity of the harness, squishiness of the human body etc... but have found it isn't possible as I will end up with my time or distance during the impact being 0 which doesn't really work very well.

Homework Statement


Homework Equations


The Attempt at a Solution



Now I have managed to work out the velocity before impact for a falling person using
Vf2 = Vi2+2a*d using:
Vi = 0
a = 9.81ms2
d = 0.6m
and have a velocity of 3.431ms

I was going to find the deceleration using either the formula Vf=Vi+a*t or Vf2=Vi2+2a*d then use F=ma to find the force but I have realized that I have no clue what the distance or time taken to decelerate may be.

So my questions are:

Is there another way to work this out?
Has anyone come across a time or distance for the deceleration of the human body crashing into something (I think ignoring the harness for now is the best idea)?
Does it depend on the mass of the victim?
Am I actually on the right track?

My boss is using the equation E=mgh to work out the potential energy of the fall. He is just moving the decimal place to change it to kN ... is this a correct way of working out the force on the body?

Thank you very much in advance!

(I need some help with questions on vector mathematics at some point as well! :) )
 
Physics news on Phys.org
Average force,
[itex]\bar{F} =\frac {\Delta(mv)}{\Delta(t)}[/itex]

I think the time taken to a halt depends on the flexibility of the body.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
8
Views
6K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
5K
  • · Replies 3 ·
Replies
3
Views
15K