Deceleration Vs time and distance

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An object decelerating from 20 m/s to 10 m/s at a constant rate of 2.50 m/s² takes 4 seconds to complete this change in speed. To calculate the distance covered during deceleration, one cannot simply multiply the change in speed by time; instead, the average velocity must be used. The average velocity in this case is 15 m/s, leading to a distance of 60 meters. Thus, the correct formula for distance involves integrating the velocity over time rather than using a straightforward multiplication of change in speed. Understanding these calculations is crucial for accurately determining motion parameters in physics.
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An object decelerates from 20 m s to 10 m s. Deceleration is a constant 2.50 m s−2.

Firstly, time taken. change in speed over deceleration? Would make it 4 seconds. Is that correct?

Secondly how do I calculate the distance covered? Is it simply change in speed x time
which would make it 40 m? Or is it more complicated than this?
 
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No. Distance is velocity times time elapsed(and not change in velocity). Since velocity changes you should integrate for distance.
 

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