Deflection of an electron due to gravity.

Homework Statement

There are two parts to the question.
A)Why is gravity not important during JJ Thomsons experiment?
b)what is the deflection due to gravity?
Given variables.
In a thomson spectromoter set at 10^4 (V/m). deflection with out the magnetic field applied equals .10 radians over a L of .050 m.
Speed of electron with magnetic field applied is 2.9x10^7 m/s.
Strength of Magnetic field is 3.4x10^-4 T.

Homework Equations

I don't know what they are....

The Attempt at a Solution

A) in the experiment the effects of gravity were negated by the application of a magnetic field perpendicular to that of the electric field, to help over come any deflection caused by gravity.
EDIT:
I thought about it a little more...would I just be using the velocity, time distance and deflection angle to solve this??
Like...a particle fired at a zero degree angle?

Last edited:

Alright so as far as I have it figured.
v(y) = gt

then take v(y)/v(x) and take the inverse tan of it to get the answer.
It gives the angle of deflection in radians. The answer I got does not match that of the book but is close enough. It's a very small number.
the answer the book was looking for was 10^-15 m.

Now if it's done by taking .5(at^2) i get another answer, but the order is wrong. It comes out to something like 1.7x10^-17 or something or other.

Any ideas what exactly they did??

Any ideas what exactly they did??
is it a GR problem or wat do you need to use GR Action or What???

General Relatvity??
No it is not. The speed is to slow.