Del operator in spherical coordinates

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SUMMARY

The del operator in spherical coordinates is expressed using the spherical unit vectors: \(\hat{r}\), \(\hat{\phi}\), and \(\hat{\theta}\). The transformation from Cartesian coordinates involves applying the chain rule to express partial derivatives in terms of spherical coordinates. The specific expressions for the unit vectors are: \(\hat{r} = \sin\theta \cos\phi \hat{x} + \sin\theta \sin\phi \hat{y} + \cos\theta \hat{z}\), \(\hat{\phi} = -\sin\phi \hat{x} + \cos\phi \hat{y}\), and \(\hat{\theta} = \cos\phi \cos\theta \hat{x} + \sin\phi \cos\theta \hat{y} - \sin\theta \hat{z}\). A recommended resource for further exploration is the MIT Mathematics webpage on the topic.

PREREQUISITES
  • Understanding of spherical coordinates and their unit vectors
  • Familiarity with the Cartesian coordinate system
  • Knowledge of partial derivatives and the chain rule
  • Basic proficiency in vector calculus
NEXT STEPS
  • Study the derivation of the del operator in spherical coordinates
  • Learn about vector calculus identities in spherical coordinates
  • Explore the application of the del operator in physics, particularly in electromagnetism
  • Review the MIT Mathematics resource on spherical coordinates for additional methods
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with vector calculus and need to understand the del operator in spherical coordinates.

tirwit
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Homework Statement


Write the del operator in spherical coordinates?


Homework Equations


I wrote the spherical unit vectors:
[tex]\hat{r}[/tex]=sin[tex]\theta[/tex].cos[tex]\phi[/tex].[tex]\hat{x}[/tex]+sin[tex]\theta[/tex].sin[tex]\phi[/tex].[tex]\hat{y}[/tex]+cos[tex]\theta[/tex].[tex]\hat{z}[/tex]
[tex]\hat{\phi}[/tex]=-sin[tex]\phi[/tex].[tex]\hat{x}[/tex]+cos[tex]\phi[/tex].[tex]\hat{y}[/tex]
[tex]\hat{\theta}[/tex]=cos[tex]\phi[/tex].cos[tex]\theta[/tex].[tex]\hat{x}[/tex]+sin[tex]\phi[/tex]+cos[tex]\theta[/tex].[tex]\hat{y}[/tex]-sin[tex]\theta[/tex].[tex]\hat{z}[/tex]


The Attempt at a Solution


I have no idea where to start... Please help, I'm going crazy with this...
 
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In cartesian coordinates, you have

[tex]\nabla = \hat{x} \frac{\partial}{\partial x}+\hat{y} \frac{\partial}{\partial y}+\hat{z} \frac{\partial}{\partial z}[/tex]

Use the chain rule to change variables to [itex]r, \varphi, \vartheta[/itex]. For example, you can write

[tex]\frac{\partial}{\partial x} = \frac{\partial r}{\partial x}\frac{\partial}{\partial r}+\frac{\partial \varphi}{\partial x}\frac{\partial}{\partial \varphi}+\frac{\partial \vartheta}{\partial x}\frac{\partial}{\partial \vartheta}[/tex]

Then express the cartesian unit vectors in terms of the spherical unit vectors. Plug everything in and simplify.
 
It seems I suggested one of the more painful ways of finding the gradient.

Here's a web page that describes several different methods you can try:

http://math.mit.edu/classes/18.013A/HTML/chapter09/section04.html
 

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