Demonstration analysis and good books?

fgyamauti
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When I try to demonstrate that lim (x^2)=4
x--->2

I found a different delta (delta=min{2-sqrt(epsilon-4),sqrt(epsilon+4)-2}, towards the one that is written in Demidovich´s book (delta=epsilon/5). Could someone help me?
Could someone tell me, too, a good algebra, calculus and real analysis book? Is it ok if i try analysis next semester absent a more advanced calculus (without calculus 2)? I need some books that explain polar coordinates too (good ones for beginner).
Thanks and sorry for my mathematical notation.
 
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You want |x^2- 4|= |(x- 2)(x+ 2)|= |x+ 2||x- 2|< \epsilon.
So we can write |x- 2|< \epsilon/|x+ 2|
But we need a value, \delta that does NOT depend on x so that is |x- 2|< \delta then |x- 2|< \epsilon/|x+ 2|. That means we want \delta< \epsilon/|x+2|.

If |x- 2|< 1 (The "1" is chosen just because it is simple. Any positive number would do.) then -1< x- 2< 1 so 1< x< 3 and then 3< x+2< 5 so that 3< |x+ 2|< 5. Then
\frac{1}{5}&lt; \frac{1}{|x+2|}&lt; 1/3
and so
\frac{\epsilon}{5}&lt; \frac{\epsilon}{|x+2|}

That is, if
|x- 2|&lt; \frac{\epsilon}{5}
and |x- 2|< 1 as assumed above to get this, we will have
|x-2|&lt; \frac{\epsilon}{|x+2|}
so
|x-2||x+2|= |x^2- 4|&lt; \epsilon
as need.

In other words, take \delta to be the smaller of \epsilon/5 or 1.

Analysis is basically the theory behind the Calculus. I would NOT take an analysis course without having completed the Calculus sequence.
 
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