- #1

- 685

- 4

##Re(z) = \frac{1}{2} \left ( z+\bar{z} \right )##

##Im(z) = \frac{1}{2i} \left ( z-\bar{z} \right )##

##Abs(z)=\sqrt{z\bar{z}}##

##Arg(z)=-i ln\left ( \frac{z}{\sqrt{z\bar{z}}} \right )##

?

2# Is correct to affirm that

##Arg(z)=-i ln\left (\sqrt{\frac{z}{\bar{z}}} \right)##

?