Density, buoyancy, and volume in static fluids

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Homework Help Overview

The discussion revolves around a problem involving buoyancy, density, and tension in static fluids, specifically focusing on a rock suspended in different liquids. The original poster presents a scenario where the tension in a string changes as the rock is immersed in air, water, and an unknown liquid.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between tension, buoyant force, and the weight of the rock. There are attempts to derive equations based on the given tensions in different fluids, with some participants questioning how to relate the buoyant force to the weight of the rock.

Discussion Status

The discussion includes various interpretations of the problem, with participants providing insights into the forces acting on the rock and how to set up equations based on the information given. Some guidance is offered regarding drawing free body diagrams and applying Archimedes' principle, but no consensus is reached on a complete solution.

Contextual Notes

There is an acknowledgment of missing information, such as the volume of the rock, which complicates the application of the buoyant force equation. Participants also note the need to clarify the relationships between the forces acting on the rock in different fluids.

Notion
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Homework Statement


A rock is suspended by a light string. When the rock is in air, the tension in the string is 35.7N . When the rock is totally immersed in water, the tension is 25.9N . When the rock is totally immersed in an unknown liquid, the tension is 19.6N .

Homework Equations


Density = m/v
buoyant force (b.f.)= density(of fluid) * gravity * Volume(of the part that is immersed in the fluid)

The Attempt at a Solution


Since we're given the tension (T) in the air, we can find the mass of the rock because T = mg in that case. Then after this I'm not sure where to go with it because since I don't know the volume of the rock I can't use the (b.f.) equation to help me at all. What am I missing?

Thanks
 
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"When the rock is totally immersed in water ..."
 
Bystander said:
"When the rock is totally immersed in water ..."

I don't see how that helps me though. If I try using that info I come up with the equation:

ρliquid * gravity * Vrock = 35.7

Still have 2 unknowns...
 
Last edited:
Notion said:
ρliquid * gravity * Vrock = 35.7
Please explain how you obtain that equation from the relevant equations you posted.
 
haruspex said:
Please explain how you obtain that equation from the relevant equations you posted.

Sorry I meant to put 19.6 instead of 35.7. So the equation should actually read:

ρliquid * gravity * Vrock = 19.6
 
Notion said:
Sorry I meant to put 19.6 instead of 35.7. So the equation should actually read:

ρliquid * gravity * Vrock = 19.6
No better. Draw a free body diagram of the rock suspended immersed in a fluid. What forces act on it?
 
Rock in water/unknown fluid:
Tension & buoyancy pointing up, of force gravity pointing down.

∑forces : Tension + B.F = mg
 
If the rock weighs 35.7N, and, when it is immersed in water, the tension in the string is 25.9N, what is the upward force exerted on the rock by the surrounding water?

Chet
 
Chestermiller said:
If the rock weighs 35.7N, and, when it is immersed in water, the tension in the string is 25.9N, what is the upward force exerted on the rock by the surrounding water?

Chet

That would be 35.7-25.9=9.8?
 
  • #10
Notion said:
That would be 35.7-25.9=9.8?
Yes. Now apply that to the other liquid.
 
  • #11
Notion said:
That would be 35.7-25.9=9.8?
From Archemides principle, what volume of water would have to be displaced to produce the 9.8 N upward force? How does that relate to the volume of the rock?

Chet
 
  • #12
Ooh I get it!

I found the volume of the rock to be .001
and I plugged in that value into the B.F equation for the unknown liquid
then I set that equal to the weight of the rock - the tension and found the density.

Thank you very much!
 

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