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Homework Statement
This is Problem 7.6 from Electronic Properties of Engineering Materials by Livingston.
"Over a wide range of frequencies, the dielectric constant of a polymer is found to be proportional to the inverse square root of frequency. (a) How does the phase velocity of EM-waves vary with wavelength in this polymer? (b) What is the ratio between phase and group velocities in this material?"
This is frustrating for many reasons, not the least of which is that the answers we've been given are in terms of wavenumber, not wavelength. The (presumed) answer follows.
Problem 7-6: (a) ##v_p = Ck^\frac{1}{3} ##, (b) ##v_g = \frac{4}{3}Ck^\frac{1}{3}## so ##\frac{v_p}{v_g} = 2##
Homework Equations
##\epsilon_r \propto \frac{1}{\sqrt{\omega}}##
Phase Velocity: ##v_p = \frac{\omega}{k}##
Group Velocity: ##v_g = \frac{\partial \omega}{\partial k}##
The Attempt at a Solution
For an EM-Wave in a non-magnetic dielectric polymer, ##\mu = \mu_0## and ##\epsilon = \epsilon_r \epsilon_0##. From the solutions to Maxwell's Equations, we produce ##\frac{\omega}{k} = (\mu \epsilon)^{-1/2}##. Thus,
##v_p = \omega / k = (\mu_0 \epsilon_0 \epsilon_r)^{-1/2}##
By adding a constant of proportionality to the given relation, I've been able to insert the equations into each other. This produced the following:
##\frac{\omega}{k} = \frac{Ac_0^2}{\sqrt{\omega}} k##
That seems to show a linear dependence on k, and the wavelength never enters into it. This problem has me running in mathematical circles; this was the only time I got an answer that didn't just prove ##v_p = c_{polymer}##.