Derivation of formula for general formula of sine equations

AI Thread Summary
The discussion centers on deriving the general formula for sine equations, specifically the expression x=nπ + (-1)^n sin^-1(a). The initial formulas provided are x=2nπ + sin^-1(a) and x=(2n+1)π - sin^-1(a), which are straightforward to understand. The more general formula's derivation is clarified by examining cases where n is even or odd, leading to a clearer understanding of the solution's structure. This insight highlights the importance of recognizing patterns in mathematical expressions. Ultimately, the discussion emphasizes the value of collaborative problem-solving in grasping complex concepts.
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My book gives the following formulas for the general solution of sine equations (if sin(x)=a)

x=2n\pi + sin^-^1(a)

and

x=(2n+1)\pi - sin^-^1(a)

Alternatively
x=n\pi + (-1)^nsin^-^1(a)

But it doesn't explain how it got them. I can easily see how they got the first two but I have no idea how they got the more general one. My teacher didn't show how it was derived either...just threw a bunch of formulas at us to remember
 
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Take the equation

x=n\pi + (-1)^n \sin^{-1}(a)

What happens if you take n even (that is: of the form 2k) and what happens if you take n odd (that is: of the form 2k+1)??
 
^ Wow, it seems so obvious now but I never would've seen had you not pointed me in the right direction, thank you!
 
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