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Derive the following equation: (mV^2/r)cos(x) = mgsin(x)
I don't know how you would exactly derive the equation but you can simplify it to:
tan(x)mg = mV^2 /r
You can also divide by the m and get tan(x)g = V^2/r ...
Any help is appreciated.
I don't know how you would exactly derive the equation but you can simplify it to:
tan(x)mg = mV^2 /r
You can also divide by the m and get tan(x)g = V^2/r ...
Any help is appreciated.