Deriving arcsin(1-2e^-t): What Chain Rule to Use?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
7 replies · 3K views
goomer
Messages
31
Reaction score
0
1. Derive arcsin(1 - 2 e ^-t)



2. The derivative of arcsin is 1/√(1-x^2)



3. I tried using the chain rule for 1 - 2 e ^-t, but that didn't work out. What should I take the chain rule of?
 
Physics news on Phys.org
goomer said:
1. Derive arcsin(1 - 2 e ^-t)
That should be "Differentiate arcsin(1 - 2e^(-t))"
goomer said:
2. The derivative of arcsin is 1/√(1-x^2)



3. I tried using the chain rule for 1 - 2 e ^-t, but that didn't work out. What should I take the chain rule of?
[tex]\frac{d}{du}arcsin(u) = \frac{1}{\sqrt{1 - u^2}}[/tex]

so

[tex]\frac{d}{dx}arcsin(u) = \frac{d}{du}arcsin(u)~\frac{du}{dx}[/tex]

Can you figure out what u is here?
 
What you have done so far is almost right. The derivative of arcsin(x) is
[tex]\frac{1}{1- x^2}[/tex]
and, in [itex]arcsin(1- 2e^{-t})[/itex], [itex]x= 1- 2e^{-t}[/itex]
So the derivative of [itex]arcsin(1- 2e^{-t})[/itex]
is
[tex]\frac{1}{1- (1- 2e^{-t})^2}[/tex]
times (the chain rule) the derivative of
[tex]1- 2e^{-t}[/tex]
 
Last edited by a moderator:
I'm still not quite sure...is it the chain rule of the entire √(1-u^2) portion?
I'm certain the derivative of arcsin is \frac{1}{\sqrt{1 - x^2}}[/tex] however.
 
Sorry, I don't know how to use the PrettyFont
1/√(1-x^2) is the derivative of arcsin, I mean
 
goomer said:
I'm still not quite sure...is it the chain rule of the entire √(1-u^2) portion?
I'm certain the derivative of arcsin is \frac{1}{\sqrt{1 - x^2}}[/tex] however.

When applying the chain rule, you only differentiate the 'u' term by itself, not the whole square root term. See Mark44's post.
 
So I am right in trying to differentiate (1 - 2 e ^-t) for the chain rule in my original problem?
 
goomer said:
I'm still not quite sure...is it the chain rule of the entire √(1-u^2) portion?
I'm certain the derivative of arcsin is \frac{1}{\sqrt{1 - x^2}}[/tex] however.

You'll need to put [ tex ] in front of your equation to (without spaces). So you should have typed [ tex ]\frac{1}{\sqrt{1 - x^2}}[ /tex ].
That's how you use the PrettyFont here (called LaTeX). Alternatively, you can also use the x2 and x2 buttons above to create su(b/p)scripts.

Sorry, just wanted to mention that :biggrin: