Deriving Basic Physic Problem Using Calculus

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Homework Help Overview

The discussion revolves around a physics problem involving a car decelerating from a speed of 15 m/s to a stop over a distance of 45 meters, with specific questions about deceleration, distance traveled at a reduced speed, and time to stop. The problem requires the application of calculus to derive the relevant equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between acceleration, velocity, and position functions through integration. Some express uncertainty about how to approach the latter parts of the problem, particularly regarding the integration constants and their implications.

Discussion Status

There is an ongoing exploration of the relationships between the functions involved, with some participants attempting to clarify the integration process. A suggestion to consider the problem in reverse has been made, indicating a potential direction for further thought. However, there is no explicit consensus on the next steps or solutions.

Contextual Notes

Participants note constraints related to time and the requirement to use calculus for deriving equations, which may limit their ability to solve the problem directly. There is also a mention of confusion regarding the concept of acceleration and its negative value in the context of deceleration.

Hypnos_16
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Homework Statement



At a distance of 45 meters from a traffic light, a car traveling 15 m/s is brought to a stop at a constant deceleration

a) What is the value of Deceleration (-5m/s)
b) How far has the car moved when its speed has been reduced to 3 m/s
c) How many seconds would the car take to come to a full stop?

Homework Equations



I really want to solve this Physics based, but we need to use calculus to derive the equations. so there's no way of showing what equations i have used already

The Attempt at a Solution



I don't have an attempt at b and c because i don't know how to start them.
Help would be appreciated, it's the last two questions i have to do on an assignment for tomorrow. Please help
 
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The acceleration function for the car is a(t) = -5 , a constant function. What are the velocity and position functions for this? (What is the relationship between a(t) and v(t)? between v(t) and x(t) ?
 
the relationship between a(t) and v(t), and v(t) and x(t) is that if you integrate a(t) you get v(t) and integrating v(t) gets x(t)
 
Hypnos_16 said:
the relationship between a(t) and v(t), and v(t) and x(t) is that if you integrate a(t) you get v(t) and integrating v(t) gets x(t)

Good! So v(t) = \int a(t) dt = \int (-5) dt gives you...?
 
Well, from what i can tell, it give you the speed at any given time.
But if that's the case i don't have the time to solve B
 
Hypnos_16 said:
Well, from what i can tell, it give you the speed at any given time.
But if that's the case i don't have the time to solve B

You get an "arbitrary constant" from the integration. What you know from the statement of the problem is that when the car begins slowing down, which is at t = 0, the speed is v(0) = 15 m/sec. What does this make the constant from your velocity integral?
 
Acceleration?
Sorry, this really isn't clicking.
 
Hypnos_16 said:

Homework Statement



At a distance of 45 meters from a traffic light, a car traveling 15 m/s is brought to a stop at a constant deceleration

a) What is the value of Deceleration (-5m/s)
b) How far has the car moved when its speed has been reduced to 3 m/s
c) How many seconds would the car take to come to a full stop?

Homework Equations



I really want to solve this Physics based, but we need to use calculus to derive the equations. so there's no way of showing what equations i have used already

The Attempt at a Solution



I don't have an attempt at b and c because i don't know how to start them.
Help would be appreciated, it's the last two questions i have to do on an assignment for tomorrow. Please help

You might find it easier to consider the problem in reverse: starting from rest, a car undergoing constant acceleration reaches a speed of 15 m/s at a distance of 45 m.

RGV
 
Hypnos_16 said:
Acceleration?
Sorry, this really isn't clicking.

Are you asking about the "-5" ? Acceleration is any change in velocity, so slowing down is a negative acceleration (what people also called a "deceleration"). The calculations of motion can be done with positive or negative accelerations; the ability to work out the velocity and position functions does not depend on the sign of a(t).
 

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