Deriving relationship between LVDT and mass spring damper

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SUMMARY

The discussion focuses on deriving the dynamic equation that relates the voltage output (V) of a Linear Variable Differential Transformer (LVDT) to the external position (x1) in a mass-spring-damper system. The established equation for the system is mx1'' + bx1' + kx = 0, where m is the mass, b is the damping coefficient, and k is the spring constant. The relationship is defined as V = Gx1, where G is the transfer function of the LVDT. Key assumptions include constant damping force and the impact of the mass hitting a stopper, which can disrupt the accelerometer's functionality.

PREREQUISITES
  • Understanding of mass-spring-damper systems
  • Knowledge of Linear Variable Differential Transformers (LVDT)
  • Familiarity with transfer functions in control systems
  • Basic principles of dynamics and acceleration measurement
NEXT STEPS
  • Research the derivation of transfer functions for LVDTs
  • Study the effects of damping in mass-spring-damper systems
  • Explore the impact of excitation frequency on LVDT performance
  • Investigate methods to minimize shock waves in accelerometer systems
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Engineers, physicists, and students involved in mechanical systems, control systems design, and sensor technology, particularly those focusing on accelerometer applications and dynamic measurements.

wu_weidong
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Homework Statement


[/B]
I have this system below.
ogyi3m.png

It is the schematic of a linear accelerometer moving horizontally, where m is the total mass of the slide, b denotes the viscous damping, and k represents the spring constant. The relative position between the moving mass and the case is measured by a linear variable differential transformer (LVDT).

How do I derive the dynamic equation describing the relationship between V, the voltage output of the LVDT, and x1 , the external position, and show that V indeed can be used to measure the external acceleration? I'm supposed to also state any assumptions made and any possible problems and remedies.

The Attempt at a Solution



I know that the mass spring damper system has the equation mx1'' + bx1' + kx = 0, and the moving core that is pulled by the mass spring damper system will induce a voltage in the LVDT. If I was given a transfer function for the LVDT, G, then I have V = Gx1. But I don't know how to link the 2 concepts together to derive the relationship.

As for the assumptions, I would say the damping force is constant, i.e. the case is smooth. I'm wondering how the mass hitting the stopper will affect the system. Should it be made of rubber to absorb the impact and to minimize the shock wave?
 
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wu_weidong said:
If I was given a transfer function for the LVDT, G, then I have V = Gx1. But I don't know how to link the 2 concepts together to derive the relationship.
?
You just stated the relationship: V = Gx1.
As for the assumptions, I would say the damping force is constant, i.e. the case is smooth.
I hope so, otherwise you're in for it!
I'm wondering how the mass hitting the stopper will affect the system. Should it be made of rubber to absorb the impact and to minimize the shock wave?
If the mass hits the stop you no longer have an accelerometer. Not until it leaves the stop again.
With any such accelerometer you have to deal with the fact that x1'' is not available; you get something like x1''exp(-at)sin(ωt + φ). As you know if you solved for x1 then took the 2nd time derivative.

More fun: is the LVDT transfer function really dynamics-free? I.e. is G really free from frequency dependence? Your LVDT is excited by an ac voltage, typically 400 Hz in aircraft or 60 Hz at home, so this alone limits the bandwidth. Then there's the question of what happens even if the excitation frequency is high enough to ignore it: if you apply a step inductance change by step-moving the core, will you get an immediate step response in V?
 

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