Deriving Standard Molar Entropy of Water

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The standard molar entropy of water varies in literature, with values around 63.45 J/mol-K to 69.9 J/mol-K commonly cited. To derive the standard molar entropy of liquid water, one can start with the entropy of gaseous water and adjust it by subtracting the heat of vaporization divided by the standard absolute temperature. Additionally, knowledge of the equilibrium constant for the formation reaction is essential for accurate calculations. This approach highlights the importance of thermodynamic principles in determining entropy values. Understanding these derivations is crucial for physics and chemistry students studying thermodynamics.
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Hello everyone, I am a second year physics student attending university, and I have a question about how the actual Standard Molar Entropy of various molecules are found and derived. I have been looking through various Thermodynamics and Chemistry books as well journals online and have all referenced water, for example, to have a standard entropy of around 70 (some are more specific, stating 63.45 J/mol-K etc, but others including some chemistry books state the standard molar entropy to be 69.9 J/mol-K.).

I am specifically interested in how the standard molar entropy of water in liquid form was found.

Thanks in advanced,
 
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If you know the standard molar entropy of gaseous water (a hypothetical state), the standard molar entropy of liquid water is that value minus the heat of vaporization divided by the standard absolute temperature. To get the standard molar entropy of liquid water, you need to measure (or otherwise know) the equilibrium constant for formation reaction.
 
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