Deriving the Divide and Average Method from Newton-Raphson Formula

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The Divide and Average Method for calculating the square root of 2 can be derived from the Newton-Raphson formula by expressing the problem as finding the root of the function F(x) = x^2 - 2. The Newton-Raphson iterative formula is applied as Xi+1 = Xi - F(Xi)/F'(Xi), where F'(x) is the derivative of F(x). By substituting F(x) and its derivative into this formula, the method simplifies to Xi+1 = 1/2 (Xi + 2/Xi), which is the desired equation. The discussion highlights the importance of correctly identifying the function and its derivative to derive the iterative method successfully. Understanding this derivation is crucial for applying the Newton-Raphson method effectively.
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Homework Statement



[Divide and average Method] Square root of 2 was computed using the formula

Xi+1 = 1/2 ( Xi + 2/Xi).------------ (1)

Derive this method from the Newton-Raphson Formula

Homework Equations





The Attempt at a Solution



Im boggled at how to derive this solution.

The equation for Newton Raphson is

F'(Xi) = (F(Xi) - 0) / Xi -(Xi+1) ------------- (2)

which can be rearranged to

Xi+1 = Xi - F(Xi) / F'(Xi)--------- (3)

does this mean that i take the derivative of the equation (1)?

(Xi+1)' =1/2(Xi+2/Xi)
= ??
 
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thedc said:

Homework Statement



[Divide and average Method] Square root of 2 was computed using the formula

Xi+1 = 1/2 ( Xi + 2/Xi).------------ (1)

Derive this method from the Newton-Raphson Formula

Homework Equations


The Attempt at a Solution



Im boggled at how to derive this solution.

The equation for Newton Raphson is

F'(Xi) = (F(Xi) - 0) / Xi -(Xi+1) ------------- (2)

which can be rearranged to

Xi+1 = Xi - F(Xi) / F'(Xi)--------- (3)

does this mean that i take the derivative of the equation (1)?

(Xi+1)' =1/2(Xi+2/Xi)
= ??

You have
x^2 = 2
or
x = \frac{2}{x}
So,
f(x) = \frac{2}{x}
Derive your equations from there.
 
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I still don't get it, do i take the derivative of 2/x?

that would be f(x)'=-2(1/x^2)
 
thedc said:
I still don't get it, do i take the derivative of 2/x?

that would be f(x)'=-2(1/x^2)

What is the Newton-Raphson method?
 
CEL said:
What is the Newton-Raphson method?

Good job guy.

/s
 
I am having the same problem.

Newton Raphson method: Xof(i+1) = xi - f(x)/f(x)'

it is used to find roots by iteration
 
Hidemons said:
I am having the same problem.

Newton Raphson method: Xof(i+1) = xi - f(x)/f(x)'

it is used to find roots by iteration

Write your equation in the form y = f(x).
Calculate f'(x).
Choose a starting value for x0.
If y - f(x0) < tolerance then end
else
Calculate x1 using Newton-Raphson formula.
Iterate
 
I think there is sufficient confusion amoung these posts to warrent another (hopefully non-confusing) post

thedc: For Newton-Raphson, you are looking for the zero of a function (F), hence, you need to express the function (F) such that F(x) = 0.

In your original post, you desire to find the answer to x for x = \sqrt{2}. Consider the more general solution for x with x = \sqrt{A} for some positive A.

Question: How can we express a function, F(x), such that it results in F(x)=0 for this problem?

Answer: Look at the x = \sqrt{A}. This is really the same as finding x^2 such that x^2 = A. Hence, one selection of F(x) might be F(x) = x^2 - A=0.

This is the "F" that is needed in the N-R method. The iterates for the solution of x are as follows:

<br /> x_{\nu+1} = x_{\nu}-\frac{F(x_{\nu})}{F&#039;(x_{\nu})}<br />

Here, F&#039;(x) is shorthand to mean \frac{d\,}{dx}F(x). Also, in your case, the vale of A is A=2. You will need an initial estimate x_{0} to start this procedure.



The key to achieve the end goal of your exercise is to do some algebra on the resulting iterate expresion once you take the derivative of F and substitute it into the expression.

Hope this helps.
 
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