Deriving the speed of a falling ball

AI Thread Summary
The discussion revolves around deriving the speed of a falling baseball influenced by air drag, which is proportional to the square of its speed. Participants address the forces acting on the ball, applying Newton's second law to understand the motion's characteristics. The terminal speed is established as vt = √(mg/D), and the conversation includes deriving the speed equation over time. A user encounters difficulty isolating the velocity in the final step but ultimately finds a straightforward solution. The thread highlights the importance of understanding motion dynamics under drag forces.
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Homework Statement


You drop a baseball from the roof of a tall building. As the ball falls, the air exerts a drag force proportional to the square of the ball's speed (f=Dv2).
  1. (a) In a diagram, show the direction of motion and indicate, with the aid of vectors, all the forces acting on the ball.
  2. (b) Apply Newton's second laws second law and infer from the resulting equation the general properties of the motion.
  3. (c) Show that the ball acquires a terminal speed that is described by vt= \sqrt{\frac{mg}{D}}
  4. (d) Derive the equation for the speed at any time.

Homework Equations


\int((a2-x2)-1)dx = \frac{1}{a}arctanh(\frac{x}{a}), where tanh(x)=(ex-e-x)/(ex+e-x)= (e2x-1)/(e2x+1)

The Attempt at a Solution


In the attachment.

I'm at a block with the last step of part d. How do I isolate v from that? Any help is appreciated.
 

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tanh^{-1}(\frac{v\sqrt{D}}{\sqrt{mg}}) = \sqrt{\frac{mg}{D}}*t
...
Finally
v = \sqrt{\frac{mg}{D}}*tanh(\sqrt{\frac{mg}{D}}*t)
 
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Likes hhhh
Oh wow. That was pretty simple in retrospect... thanks.
 
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