Deriving the Vector Identity: $\nabla(\vec{A} \cdot \vec{B})$

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Homework Help Overview

The discussion revolves around deriving the vector identity $\nabla(\vec{A} \cdot \vec{B})$. Participants are exploring the mathematical context of vector calculus, specifically focusing on the properties and manipulations of vector fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants attempt to derive the identity using analytical methods but express frustration at reaching a dead end. Others question the validity of referring to the expression as an identity, noting that identities typically involve equal signs. There is also mention of a desire to learn new methods due to time constraints related to an upcoming exam.

Discussion Status

The discussion is ongoing with participants sharing their attempts and questioning the assumptions behind the identity. Some guidance is offered regarding the approach to take, with suggestions to simplify the derivation by omitting certain elements.

Contextual Notes

Participants express urgency due to an impending exam and mention challenges with formatting their work in LaTeX, which may affect the clarity of their contributions.

Xsnac
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Homework Statement


I'm trying to derive the vector identity:
$$\nabla(\vec{A} \cdot \vec{B})$$

Homework Equations


$$ \nabla(\vec{A} \cdot \vec{B})=(\vec{B} \cdot \nabla) \vec{A} + ( \vec{A} \cdot \nabla ) \vec{B} + \vec{B} \times (\nabla \times \vec{A})+ \vec{A} \times ( \nabla \times \vec{B})$$

The Attempt at a Solution


I tried to do it using analitical methods and I think I hit a dead end.
I tried everything, even the reverse start from the $$(\vec{B} \cdot \nabla) \vec{A} + ( \vec{A} \cdot \nabla ) \vec{B} + \vec{B} \times (\nabla \times \vec{A})+ \vec{A} \times ( \nabla \times \vec{B})$$ part but this is the best I could get

Scan.jpg
At this point I'm even willing to learn a totally new method .. I have an exam tomorrow and this is the only one I can't get right.​
 
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Xsnac said:

Homework Statement


I'm trying to derive the vector identity:
$$\nabla(\vec{A} \cdot \vec{B})$$
This isn't an identity. Identities generally have equal signs in them.

Homework Equations


$$ \nabla(\vec{A} \cdot \vec{B})=(\vec{B} \cdot \nabla) \vec{A} + ( \vec{A} \cdot \nabla ) \vec{B} + \vec{B} \times (\nabla \times \vec{A})+ \vec{A} \times ( \nabla \times \vec{B})$$

The Attempt at a Solution


I tried to do it using analytical methods and I think I hit a dead end.
I tried everything, even the reverse start from the $$(\vec{B} \cdot \nabla) \vec{A} + ( \vec{A} \cdot \nabla ) \vec{B} + \vec{B} \times (\nabla \times \vec{A})+ \vec{A} \times ( \nabla \times \vec{B})$$ part but this is the best I could get

Scan.jpg
At this point I'm even willing to learn a totally new method .. I have an exam tomorrow and this is the only one I can't get right.​
Speaking personally, I'm not really prone to putting in the effort to follow your chicken scratches. Why don't you try organizing your work in digestible chunks and posting it in LaTeX.
 
vela said:
This isn't an identity. Identities generally have equal signs in them.Speaking personally, I'm not really prone to putting in the effort to follow your chicken scratches. Why don't you try organizing your work in digestible chunks and posting it in LaTeX.

I don't have 3 hours to format a text... I'm practicing for tomorrow's exam... I put a lot of effort to write the small pieces of latex code in this post aswel. (forgot all the syntax and got to relearn it today..)
And I'm looking for some other way since mine I think is a dead-end.
 
Well, the approach you're taking is the one I would use. Omit the unit vector stuff. It just clutters up the derivation.
 

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