Deriving v(t) from i(t) in a Series Circuit: Finding V Across Z | Homework Help

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SUMMARY

The discussion focuses on deriving the voltage v(t) across the impedance Z in a series circuit consisting of a 0.5H inductor, a 0.01F capacitor, a second 0.5H inductor, and a 10Ω resistor, driven by the current source i(t) = 10cos(10t). The impedance Z(s) is determined to be (s + 100)/(s + 10), and the frequency-dependent impedance Z(jω) is expressed as j((ω² - 100)/ω) + 10. The correct approach to find v(t) involves using Ohm's Law in the s-domain, specifically V(s) = I(s)Z(s), and applying the Laplace transform to the current to derive I(s) before calculating the voltage.

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  • Understanding of series circuits and components (inductors, capacitors, resistors)
  • Familiarity with Laplace transforms and their application in circuit analysis
  • Knowledge of impedance in the s-domain and frequency domain
  • Proficiency in applying Ohm's Law in electrical engineering contexts
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  • Study Laplace transforms and their application in circuit analysis
  • Learn about calculating impedance in both s-domain and frequency domain
  • Explore the concept of inverse Laplace transforms for voltage and current calculations
  • Review Ohm's Law and its implications in AC circuit analysis
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Electrical engineering students, circuit designers, and anyone involved in analyzing series circuits and AC signals will benefit from this discussion.

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Homework Statement



I've been given a series circuit with a .5H inductor .01F cap, .5H inductor and 10Ω resistor in series.

This circuit is connected to a source i(t) = 10cos(10t) and I need to find v(t) across Z

Homework Equations


From the givens I've found the Z(s) to be s+100/s+10 and Z(jω) to be j((ω^2-100)/ω)+10

The Attempt at a Solution



I believe I need to use Ohm's law V=IR to find V. So if I multiply j((ω^2-100)/ω)+10 by 10cos(10t) I should get a v(t) but I think I'm doing something wrong with this.
 
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what you need to do is make sure you are in the s-domain, so V(s) = I(s)Z(s), you need to perform laplace transform to the current output to obtain I(s), then you can multiply that with the frequency dependent impedance, then finally get your answer from the inverse laplace of the product
 

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